Given:
Temperature of water, 
= 
=273 +(-6) =267 K
Temperature surrounding refrigerator, 
= 
=273 + 21 =294 K
Specific heat given for water, 
= 4.19 KJ/kg/K
Specific heat given for ice, 
= 2.1 KJ/kg/K
Latent heat of fusion, 
= 335KJ/kg
Solution:
Coefficient of Performance (COP) for refrigerator is given by:
Max 
= 
= 
= 9.89
Coefficient of Performance (COP) for heat pump is given by:
Max 
= 
= 10.89
Answer:
576.21kJ
Explanation:
#We know that:
The balance mass 
so, 
#Also, given the properties of water as;
#We assume constant properties for the steam at average temperatures:
#Replace known values in the equation above;
#Using the mass and energy balance relations;
#We have 
: we replace the known values in the equation as;
#Hence,the amount of heat transferred when the steam temperature reaches 500°C is 576.21kJ
Volume=Hh(b1+b2)/2. b1 and b2 are the base of the trapezoid
Answer:
1
Created on Nov 3, 2018 @author: ASLand
7import atexit
#Read, nanes of both files
Rrintll"Enter tvo files to be compared below
userliamel input ("Enter the nome of the first file: ")
userliame2 input("Enter the name of the second file: ")
ROpen each file
f1 - open(userNamel, r')
@17 f2 = opan(useriame 2, )
tread all the lines into a list
d1 f1.readlines ()
d2 f2.readlines()
re equivalent, print "Yes" else pri
oiterate, and conpare
#11
the
y
if dl == d2:
print("Yes")
atexit
elif for i in range(@, min(len (d1), len(d2))):
if di[i]!=d2[i]:
PCint("No")
print(d1[i])
pcint(d2[])
Answer:
11 toes on one foot? and 5 one the other or just 11 toes?
your NO HINT threw me off
Explanation:
