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Assoli18 [71]
3 years ago
5

All chemical reactions need the same amount of activation energy. A True

Chemistry
1 answer:
Blizzard [7]3 years ago
6 0
Answer:
false

explanation:
it is possible to lower the amount of activation energy required in a system. the process of speeding up a reaction by reducing its activation energy is known as catalyst.
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13. What is the total pressure inside the container​
nasty-shy [4]

<u>Answer:</u> The total pressure inside the container is 77.9 kPa

<u>Explanation:</u>

Dalton's law of partial pressure states that the total pressure of the system is equal to the sum of partial pressure of each component present in it.

To calculate the total pressure inside the container, we use the law given by Dalton, which is:

P_T=p_{N_2}+p_{O_2}+p_{Ar}

We are given:

Vapor pressure of oxygen gas, p_{O_2} = 40.9 kPa

Vapor pressure of nitrogen gas, p_{N_2} = 23.3 kPa

Vapor pressure of argon, p_{Ar} = 13.7 kPa

Putting values in above equation, we get:

p_T=23.3+40.9+13.7\\\\p_{T}=77.9kPa

Hence, the total pressure inside the container is 77.9 kPa

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How many carbon dioxide molecules should be added to the products side to obey the law of conservation of matter?
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Answer:

four A

Explanation:

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What process would best separate a solution of liquid water and liquid rubbing alcohol
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g 304 mL of a 0.36 M potassium hydroxide solution is added to 341 mL of a 0.51 M lithium hydroxide solution. Calculate the pOH o
Liono4ka [1.6K]

Answer:

<u><em></em></u>

  • <u><em>pOH = 0.36</em></u>

Explanation:

Both <em>potassium hydroxide</em> and <em>lithium hydroxide </em>solutions are strong bases, so you assume 100% dissociation.

<u>1. Potassium hydroxide solution, KOH</u>

  • Volume, V = 304 mL = 0.304 liter
  • Molarity, M = 0.36 M
  • number of moles, n = M × V = 0.36M × 0.304 liter = 0.10944 mol
  • 1 mole of KOH produces 1 mol of OH⁻ ion, thus the number of moles of OH⁻ is 0.10944

<u>2. LIthium hydroxide, LiOH</u>

  • Volume, V = 341 mL = 0.341 liter
  • Molarity, M = 0.51 M
  • number of moles, n = M × V = 0.341 liter × 0.51 M = 0.17391 mol
  • 1mole of LiOH produces 1 mol of OH⁻ ion, thus the number of moles of OH⁻ is 0.17391

<u />

<u>3. Resulting solution</u>

  • Number of moles of OH⁻ ions = 0.10944 mol + 0.17391 mol = 0.28335 mol

  • Volume of solution = 0.304 liter + 0.341 liter = 0.645 liter

  • Molar concentration = 0.28335 mol / 0.645 liter = 0.4393 M

<u />

<u>4. </u><em><u>pOH</u></em>

      pOH=-\log [OH^-]=-\log (0.439)=0.36   ← answer

5 0
3 years ago
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