1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
zzz [600]
3 years ago
10

A construction company distributes its products by trucks loaded at its loading station. A backacter in conjunction with trucks

are used for this purpose. If it was found out that on an average of 12 trucks per hour arrived and the average loading time was 3 minutes for each truck. A truck must queue until it is loaded. The backacter’s daily all-in rate is GH¢ 1000 and that of the truck is GH¢ 400.
a) Compute the operating characteristics: L, Lq, W, Wq, and P.

b) The company is considering replacing the backacter with a bigger one which will have an average service rate of 1.5 minutes to serve trucks waiting to have their schedules improved. As a manager, would you recommend the new backacter if the daily all-in rate is GH¢ 1300.

c) The site management is considering whether to deploy an extra backwater to assist the existing one. The daily all-in-rate and efficiency of the new backwater is assumed to be the same as that of the existing backwater. Should the additional backwater be deployed?
Engineering
1 answer:
blagie [28]3 years ago
6 0

Answer:

a) L = 1.5

L_q = 0.9

W =  \dfrac{1 }{8 } \, hour

W_q =  \dfrac{3}{40 } \, hour

P = \dfrac{3}{5 }

b) The new backacter should be recommended

c) The additional backacter should not be deployed

Explanation:

a) The required parameters are;

L = The number of customers available

L = \dfrac{\lambda }{\mu -\lambda }

μ = Service rate

L_q = The number of customers waiting in line

L_q = p\times L

W = The time spent waiting including being served

W = \dfrac{1 }{\mu -\lambda }

W_q = The time spent waiting in line

W_q = P \times W

P = The system utilization

P = \dfrac{\lambda }{\mu  }

From the information given;

λ = 12 trucks/hour

μ = 3 min/truck = 60/3 truck/hour = 20 truck/hour

Plugging in the above values, we have;

L = \dfrac{12 }{20 -12 } = \dfrac{12 }{8 } = 1.5

P = \dfrac{12 }{20 } = \dfrac{3}{5 }

L_q = \dfrac{3}{5 } \times \dfrac{3}{2 } = \dfrac{9}{10 } = 0.9

W = \dfrac{1 }{20 -12 } =  \dfrac{1 }{8 } \ hour

W_q = \dfrac{3}{5 } \times \dfrac{1}{8 } = \dfrac{3}{40 } \, hour

(b) The service rate with the new backacter = 1.5 minutes/truck which is thus;

μ = 60/1.5 trucks/hour = 40 trucks/hour

P = \dfrac{12 }{40  } = \dfrac{3}{10}

W = \dfrac{1 }{40 -12 } =  \dfrac{1 }{38 } \, hour

W_q = \dfrac{3}{10 } \times \dfrac{1}{38 } = \dfrac{3}{380 } \, hour

λ = 12 trucks/hour

Total cost = mC_s + \lambda WC_w

m = 1

C_s = GH¢ = 1300

C_w = 400

Total cost with the old backacter is given as follows;

1 \times 1000 + 12 \times \dfrac{1}{8}  \times 400 = \$ 1,600.00

Total cost with the new backacter is given as follows;

1 \times 1300 + 12 \times \dfrac{1}{38}  \times 400 = \$ 1,426.32

The new backacter will reduce the total costs, therefore, the new backacter is recommended.

c)

Here μ = 3 min/ 2 trucks = 2×60/3 truck/hour = 40 truck/hour

\therefore W = \dfrac{1 }{40 -12 } =  \dfrac{1 }{38 } \, hour

Total cost with the one backacter is given as follows;

1 \times 1000 + 12 \times \dfrac{1}{8}  \times 400 = \$ 1,600.00

Total cost with two backacters is given as follows;

2 \times 1000 + 12 \times \dfrac{1}{38}  \times 400 = \$ 2,126.32

The additional backacter will increase the total costs, therefore, it should not be deployed.

You might be interested in
Draw the logic circuit for each of the following. For each gate, determine if it generates either EVEN or ODD parity bit and fin
omeli [17]

Answer:

a) 4-input XOR, input data-1001  = 0 Even parity Bit

b)  5-input XOR, input data-10010 = 0 Even parity Bit  

c) 6-input XOR, input data-101001 = 1 Even parity Bit

d) 7-input XOR, input data 1011011 = 1 Even parity Bit

Explanation:

a) 4-input XOR, input data-1001  ;  generates 0 Even parity Bit

b)  5-input XOR, input data-10010 ; generates 0 Even parity Bit  

c) 6-input XOR, input data-101001 ; generates 1 Even parity Bit

d) 7-input XOR, input data 1011011 ; generates 1 Even parity Bit

Attached below is the Logic circuits of the data inputs

8 0
3 years ago
C+ Write a program that converts degrees Fahrenheit to Celsius using the following formula. degreesC = 5(degreesF – 32)/9
Yanka [14]

Answer:

Written in C++

#include<iostream>

#include<cmath>

using namespace std;

int main()

{

float degreeC, degreeF;

cout<<"Degree Fahrenheit: ";

cin>>degreeF;

degreeC = 5 * (degreeF - 32)/9;

cout<<"Degree Celsius: "<<degreeC<<" C";  

return 0;

}

Explanation:

The question requests that input should be in degree Fahrenheit

Declare all necessary variables

float degreeC, degreeF;

Prompt user for input in degrees Fahrenheit as stated in the question

cout<<"Degree Fahrenheit: ";

Get User Input

cin>>degreeF;

Convert degree Fahrenheit to Celsius

degreeC = 5 * (degreeF - 32)/9;

Display output

cout<<"Degree Celsius: "<<degreeC<<" C";  

4 0
3 years ago
Which statement describes the wave pattern of a high pitch
olga55 [171]

Answer:

I hope this helps the tops of the waves are close together

8 0
3 years ago
A 65% efficient turbine receives 2 m^3/s of water from a reservoir. The reservoir water surface is 45 m above the centerline of
laiz [17]

Answer:

P_{out} = 508.071 kW

Given:

efficiency of the turbine, \eta = 65% = 0.65

available gross head,  H_{G} = 45 m

head loss,  H_{loss} = 5 m

Discharge, Q =  2 m^{3}

Solution:

The nozzle is 100% (say)

Available power at the inlet of the turbine,  P_{inlet} is given by:

P_{inlet} = \rho Qg(H_{G} - H_{loss})                  (1)

where

\rho = density of water = 997 kg/m^{3}

acceleration due to gravity, g = 9.8 m^{2}

Using eqn (1):

P_{inlet} = 997\times 2\times 9.8(45 - 5) = 781.65 kW

Also, efficency, \eta is given by:

\eta = \frac{P_{out}}{P_{inlet}}

0.65 = \frac{P_{out}}{781.648\times 1000}

P_{out} = 0.65\times 781.648\times 1000 = 508071 W = 508.071 kW

P_{out} = 508.071 kW

3 0
3 years ago
Inhalation is the most common way for a(n)
Mademuasel [1]

inhalation is the most common way for chemical to enter the body

6 0
3 years ago
Other questions:
  • Decide how the sketches below would be listed, if they were listed in order of decreasing force between the charges. That is, se
    9·1 answer
  • A robot was able to detect a burning smell at a shopping mall and prevent a major disaster. Which function enabled the robot to
    15·1 answer
  • A hypothetical accumulator processor uses one of the following 16-bit instruction formats, depending on the instruction.(a) (10
    6·1 answer
  • Which timeline shows the correct order of contributions made to the discovery of DNA?
    6·2 answers
  • Exercise 1. (Sum of Integers) Implement the functions sum_iter() and sum_rec() in sum_of_ints.py that take an integer n as argum
    9·1 answer
  • A fuel oil is burned with air in a furnace. The combustion produces 813 kW of thermal energy, of which 65% is transferred as hea
    13·1 answer
  • A cylindrical 1045 steel bar is subjected to repeated compression-tension stress cycling along its axis. If the load amplitude i
    10·1 answer
  • If you always follow the same five steps to get ready for school, then you are following an algorithm.
    5·2 answers
  • The component has an exponentially distributed reliability with a mean of 2000 hours what is the probability that it will fail a
    8·1 answer
  • Exercise 6.4.8: Sum Two Number
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!