A machine designed to stretch a stiff spring uses 1,550 J of energy to stretch the spring. If the work output is 1,200 J, what i
1 answer:
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Answer:
6.7 ×
Explanation:
Initial P = Final P
(1.8 × 0) + (.0075 × 0) = (1.8 × x) + (.0075 × 16)
-.12 + 1.8x
x = .0067
Answer:
The width of the slit is 0.4 mm (0.00040 m).
Explanation:
From the Young's interference expression, we have;
(λ ÷ d) = (Δy ÷ D)
where λ is the wavelength of the light, D is the distance of the slit to the screen, d is the width of slit and Δy is the fringe separation.
Thus,
d = (Dλ) ÷ Δy
D = 3.30 m, Δy = 4.7 mm (0.0047 m) and λ = 563 nm (563 × m)
d = (3.30 × 563 × ) ÷ (0.0047)
= 1.8579 × ÷ 0.0047
= 0.0003951 m
d = 0.00040 m
The width of the slit is 0.4 mm (0.00040 m).