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3 years ago

Compare the trends for atomic size and first ionization energy.

Chemistry

1 answer:

bazaltina [42]3 years ago

6 0

Explanation:

On a periodic table, the atomic size is depicted by the radius of the atom.

Across a period, the atomic radius reduces progressively from left to right.

Down the group from top to bottom, atomic radii increases progressively.

For the ionization energy, from left to right, across the period, it increases progressively and down a group it reduces.

These two trends are related in that as the atomic radius decreases across the period there is an increasing nuclear charge which is not compensated for by the the successive shells of electrons being added. This also similar down the group.

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How can a Hydrogen atom turn into a Hydrogen ion (H+)?

Butoxors [25]

Answer:

By losing an electron

Explanation:

Electrons have a negative charge. So, losing one would give an element a more positive charge. You can usually find a hydrogen ion (H+) in substances like acids.

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3 years ago

How many moles of iron in a sample that contains 7.91×10^23 atoms of iron?

vazorg [7]

Answer: 1.31

Explanation:

No.of moles = given no.of atoms/Avagadro number

= 7.91×10^23 / 6.022 x 10^23

= 1.31

therefore, no.of moles = 1.31

Hope it helped u,

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5 0

3 years ago

Calculate the pH of a 0.50 M HIO. The Ka of hypoiodic acid, HIO, is 2.3x10–11.0.305.325.479.474.80

never [62]

Answer:

pH = 5.47

Explanation:

The equilibrium that takes place is:

HIO ↔ H⁺ + IO⁻

Ka = $\frac{[H+][IO-]}{[HIO]}$ = 2.3 * 10⁻¹¹

At equilibrium:

[HIO] = 0.5 M - x

[H⁺] = x

[IO⁻] = x

Replacing those values in the equation for Ka and solving for x:

$Ka=\frac{x^2}{0.5-x}=2.3*10^{-11} \\x^2=(2.3*10^{-11})(0.5-x)\\x^2=1.15*10^{-11}-2.3*10^{-11}x\\x^2+2.3*10^{-11}x-1.15*10^{-11}=0\\x=3.39*10^{-6}$

Then [H⁺]=3.39 * 10⁻⁶, thus pH = 5.47

7 0

3 years ago

What are the 5 areas of chemistry

shepuryov [24]

The 5 main branches of chemistry are physics, analytical, biochemistry, organic chemistry, and inorganic chemistry.

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3 years ago

What is formed when hydrobromic acid, hbr, and calcium hydroxide, ca(oh)2, are combined?

Lorico [155]

This is an acid – base reaction and this always result a salt and water in a neutralization reaction. 

The salt that is formed will be calcium bromide (calcium is located in group 2 so calcium bromide has a formula of CaBr2)

so essentially we got:

HBr + Ca(OH)2 ------> CaBr2 + H2O

balancing the elements: 

2HBr(aq) + Ca(OH)2(aq) --------> CaBr2(aq) + 2H2O(l)

6 0

3 years ago