Answer:
32 pounds
Explanation:
The amount of water in the 200 pound person is
200 * 60% = 200*0.6 = 120 pounds
Of the 120 pounds, a third of this is extracellular fluid, the amount of extracellular fluid is
120 / 3 = 40 pounds
20 % of this is in the blood, which amounts to
40 * 20% = 40 * 0.2 = 8 pounds
The rest is interstitial fluid, which is
40 - 8 = 32 pounds
Answer:
Explanation:
The remaining amount of a radioactive isotope is found as the product of the original amount by (1/2) raised to the number of half-lives elapsed. The formla is:
Where M is the remaining amoun, M₀ i s the initial amount, and n is the number of half-lives.
Here, 1/64 of the original carbon-14 remained, meaning that M/M₀ = 1/64.
Then, you can substitute in the equation and solve:
Then, 6 half-lives elapsed since the mastodon died and the remains were dated.
Then, you must multiply 6 by the <em>half-life </em>time:
- 6 × 5730 years = 34,380 years ← answer
Answer:
A. structure of the classroom
Explanation:
According to the Creative Curriculum model, the _ structure of the classroom_ sets the context for teaching and learning.
In creative curriculum model children learn through creative and active learning strategy. Creative curriculum are implemented through structure of classrooms. Creative curriculum stands to enhance skill of the the students and inculcate in them passion for learning.
Answer : The correct option is, (A) 
Solution : Given,
Volume of mercury at temperature 
= 
As we know that the mercury is a liquid substance. So, we have to apply the volume of expansion of the liquid.
Formula used for the volume expansion of liquid :
![V_{T}=v_{1}[1+\gamma (T_{2}-T_{1})]](https://tex.z-dn.net/?f=V_%7BT%7D%3Dv_%7B1%7D%5B1%2B%5Cgamma%20%28T_%7B2%7D-T_%7B1%7D%29%5D)
or,
![V_{2}=V_{1}[1+\gamma (T_{2}-T_{1})]](https://tex.z-dn.net/?f=V_%7B2%7D%3DV_%7B1%7D%5B1%2B%5Cgamma%20%28T_%7B2%7D-T_%7B1%7D%29%5D)
where,
= volume of liquid at temperature 
= volume of liquid at temperature
= volume of liquid at temperature 
= volume expansion coefficient of mercury at is 0.00018 per centigrade (Standard value)
Now put all the given values in the above formula, we get the volume of mercury at .
![V_{2}=0.002[1+0.00018(50-20)]=0.0020108m^3](https://tex.z-dn.net/?f=V_%7B2%7D%3D0.002%5B1%2B0.00018%2850-20%29%5D%3D0.0020108m%5E3)
Therefore, the volume of mercury at is,
