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Answer:The Aluminum loses a
little more than twice the heat of the Copper.Explanation:<span>
Since specific heat is part of the equation. A smaller specific heat will
create a smaller heat gain or loss. </span>
<span>Hope this helped!!!!</span></span>
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If the net force on a block is zero, the block will move at constant velocity
Explanation:
We can answer this question by applying Newton's second law of motion, which states that the net force on an object is equal to the product between its mass and its acceleration:
(1)
where
is the net force on the object
m is its mass
a is its acceleration
In this problem, we have a block, and the net force on it is zero:

According to eq.(1), this also implies that

So, the acceleration of the block is zero.
However, acceleration is the rate of change of velocity of a body:

where
is the change in velocity in a time of
. Since the acceleration is zero, this means that
, and therefore the velocity of the object is constant.
Learn more about Newton's second law:
brainly.com/question/3820012
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The reasoning is wrong if we look into Newton's Law of gravitation.
Newton's law of gravitation states that every particle in the universe attracts every other particle with a force that is directly proportional to the product of their masses and inversely proportional to the square of the distance between their centers.
The law is written as follows;


The distance between the two particles, is a function of force and their masses not necessarily time of motion.
In the given problem only time of motion was considered which is wrong.
Thus, the reasoning is wrong if we look into Newton's Law of gravitation.
Learn more here: brainly.com/question/19680441
Answer:
Two oxygen atoms
Explanation:
The majority of the oxygen in the air in our atmosphere consists of molecular oxygen (
), which consists of 2 atoms of oxygen, since free oxygen mainly form covalent bonds with other atoms of oxygen.
A small fraction of the oxygen, however, in the ozone form, which consists of 3 atoms of oxygen bond together (
).