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3 years ago

5

How much current must flow through a wire to make a magnetic field as strong as Earth's field (5.00 x 10^-5 T) 1.00 m away from

the wire?

1 answer:

torisob [31]3 years ago

7 0

Answer:

250 A

Explanation:

B = 5 x 10^-5 T, r = 1 m

Let current be i.

the magnetic field due to a straight current carrying conductor is given by

B = μ0 / 4π x 2i / r

5 x 10^-5 = 10^-7 x 2 x i / 1

i = 250 A

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Answer:

L= 27.42m

Explanation:

We have the variables

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4 years ago

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Answer

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3 years ago

Spin dynamics during chirped pulses: applications to homonuclear decoupling and broadband excitation

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2 years ago

Which sentence best describes a role of gravity in the formation of the

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3 years ago

An 89.0 kg fullback moving east with a speed of 5.6 m/s is tackled by an 85.0 kg opponent running west at 2.84 m/s, and the coll

Korolek [52]

Answer:

a. $v_f=1.477m/s$

b. Δ $K=1558.3J$

c. $E_k=1034.7 J$

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b).

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d).

All of which has been lost as mechanical energy, and is now thermal energy warmer football players, noise a loud crunch for example.

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3 years ago