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3 years ago

5

How much current must flow through a wire to make a magnetic field as strong as Earth's field (5.00 x 10^-5 T) 1.00 m away from

the wire?

1 answer:

torisob [31]3 years ago

7 0

Answer:

250 A

Explanation:

B = 5 x 10^-5 T, r = 1 m

Let current be i.

the magnetic field due to a straight current carrying conductor is given by

B = μ0 / 4π x 2i / r

5 x 10^-5 = 10^-7 x 2 x i / 1

i = 250 A

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Answer:

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Explanation:

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$E_{fp}=E_{ki}\\\\(m+M)gh=\frac{1}{2}mv^2$

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Answer:

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Since the car starts from rest, v₀ =0.
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