Answer:
The distance from charge 5 μ C = 26.45 cm and the distance from - 4 μ C is 23.55 cm.
Explanation:
Given that
q₁ = 5 μ C
q₂ = - 4 μ C
The distance between charges = 50 cm
d= 50 cm
Lets take at distance x from the charge μ C ,the electrical field is zero.
That is why the distance from the charge - 4 μ C = 50 - x cm
We know that ,electric field is given as
Therefore the distance from charge 5 μ C = 26.45 cm and the distance from - 4 μ C is 23.55 cm.
Answer:
16.45 m/s
Explanation:
Let y be the vertical distance and x be the horizontal distance
We are given that
The altitude of hang glider increasing at the rate=
The shadow of the glider moves along the ground at speed=
We have to find the magnitude of glider's velocity.
We know that
Magnitude of velocity=
Substitute the values
Hence, the magnitude of glider's velocity=16.45 m/s
What do you think? how long does your hand touch fire until it feels heat.