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andre [41]
2 years ago
14

A gorilla weighs 8.00x10^2N and swings from vine to vine. As the gorilla grads a new vine, both vines make an angle of 30 degree

s with the verticle. In such a condition of static equillibrium what is the net force on the vine?
Physics
1 answer:
Yakvenalex [24]2 years ago
6 0

Answer:

461.88 N  

Explanation:

Let tension in each vine be T .

The vertical component of this tension of both the vine will add up and balance the weight .

2T cos 30 = mg

2 T x cos 30 = 800

T  = 800 / (2 x cos30 )

= 461.88 N  

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An iron wire has a length of 1.50 m and a cross sectional area of 0.290 mm2. If the resistivity of iron is 10.0 ✕ 10−8 Ω · m and
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Answer:

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Explanation:

Applying,

V = IR

I = V/R..................... Equation 1

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But,

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Sustitute equation 2 into equation 1

V = AV/Lρ............... Equation 3

From the question,

Given: V = 0.7 V, A = 0.290 mm² = 2.9×10⁻⁷ m², L = 1.5 m, ρ = 10×10⁻⁸ Ω.m

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I = (0.7× 2.9×10⁻⁷)/(1.5× 10×10⁻⁸ )

I = (2.03×10⁻⁷)/(15×10⁻⁸)

I = 1.35 A

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