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andre [41]
2 years ago
14

A gorilla weighs 8.00x10^2N and swings from vine to vine. As the gorilla grads a new vine, both vines make an angle of 30 degree

s with the verticle. In such a condition of static equillibrium what is the net force on the vine?
Physics
1 answer:
Yakvenalex [24]2 years ago
6 0

Answer:

461.88 N  

Explanation:

Let tension in each vine be T .

The vertical component of this tension of both the vine will add up and balance the weight .

2T cos 30 = mg

2 T x cos 30 = 800

T  = 800 / (2 x cos30 )

= 461.88 N  

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Answer:

The other angle is 120°.

Explanation:

Given that,

Angle = 60

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R=\dfrac{v^2\sin(2\theta)}{g}...(I)

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R=\dfrac{v^2\sin(2(\alpha-\theta))}{g}....(II)

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\dfrac{v^2\sin(2\theta)}{g}=\dfrac{v^2\sin(2(\alpha-\theta))}{g}

\sin(2\theta)=\sin(2\times(\alpha-\theta))

\sin120=\sin2(\alpha-60)

120=2\alpha-120

\alpha=\dfrac{120+120}{2}

\alpha=120^{\circ}

Hence, The other angle is 120°

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