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3 years ago

8. What is the % Al in Aluminum chromate?

Chemistry

1 answer:

Wittaler [7]3 years ago

8 0

13.4255 ‎ ‎ ‎ ‎ ‎ ‎

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Which subatomic particle has negligible mass and travels around outside the nucleus?

likoan [24]

<span>Electron because it is incredibly small. like 1840 times smaller than the proton. and it travels around the proton. The nucleus is made of proton and neutron and electron travels around it.</span>

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3 years ago

The solution set of axequalsb is the set of all vectors of the form wequalspplusbold v subscript h, where bold v subscript h is

ELEN [110]

Answer : Incorrect

Explanation : In the given solution set of Ax = b;
is set of all vectors to form w= p + $V_{h}$
here $V_{h}$ is is any solution of the equation Ax = 0;

this stands to be incorrect, as the correct would only exists when some vector p is found to be like this Ap=b

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4 years ago

Select the correct answer.

kifflom [539]

Answer:

At a given temperature, a system of particles can be considered as point masses (m) each moving at a certain translational velocity (v). The motion of these particles can be defined in terms of their average translational kinetic energy which is responsible for the heat transfer during molecular collisions and therefore the temperature of the system.

The kinetic temperature T is given in terms of the average translational kinetic energy as:

T = 2/3k(Kinetic energy)

T = 2/3k(1/2*m*v²)

where K = Boltzmann constant

Ans: C) Average translational kinetic energy

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3 years ago

Is chromium sediment, igneous, or Metamorphic Rock?

Irina18 [472]

Http://geology.com/minerals/chromite.shtml

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3 years ago

2Na(s) + 2H2O(l) → 2NaOH(aq) + H2(g) When 2 moles of Na react with water at 25°C and 1 atm, the volume of H2 formed is 24.5 L. C

olga nikolaevna [1]

Answer:

Magnitude of work done = 24.28 J

Explanation:

No. of moles = Reacting mass/ Molar mass

Reacting mass of Na = 0.45 g

Molar mass of sodium = 23g/mol

∴ No. of moles of sodium = 0.45/23 = 0.0196 mole

If 2 moles of Na react with water at 25°C and 1 atm, 24.5 L of H₂ was formed.

∴ when 0.0196 mole of Na react with water under the same conditions, (24.5×0.0196)/2 L of H₂ will be formed.

⇒ (24.5×0.0196)/2 L = 0.24 L

0.24 L × 1 atm = 0.24 L . atm

Since 1 L · atm = 101.3 J

∴ 0.24 L . atm = (0.24 L . atm ×101.3)/1 = 24.28 J

Magnitude of work done = 24.28 J

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3 years ago