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Damm [24]
3 years ago
14

A graph labeled velocity versus time with horizontal axis time (seconds) and vertical axis velocity (meters per second). A blue

line runs straight across at 2 units on the vertical axis for all horizontal axis values.
Based on the graph of velocity over time, which could be the initial velocity and the final velocity for this graph?

initial = 0 m/s; final = 2.5 m/s
initial = 2.5 m/s; final = 2.5 m/s
initial = 3.0 m/s; final = 6.0 m/s
initial = 6.0m/s; final = 3.0 m/s
Physics
1 answer:
jekas [21]3 years ago
5 0

Answer:

B

Explanation:

It's because the line keeps going straight meaning it has a constant velocity from beginning to end.

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(a) If a proton with a kinetic energy of 6.2 MeV is traveling in a particle accelerator in a circular orbit with a radius of 0.5
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Answer:

The fraction of its energy that it radiates every second is 3.02\times10^{-11}.

Explanation:

Suppose Electromagnetic radiation is emitted by accelerating charges. The rate at which energy is emitted from an accelerating charge that has charge q and acceleration a is given by

\dfrac{dE}{dt}=\dfrac{q^2a^2}{6\pi\epsilon_{0}c^3}

Given that,

Kinetic energy = 6.2 MeV

Radius = 0.500 m

We need to calculate the acceleration

Using formula of acceleration

a=\dfrac{v^2}{r}

Put the value into the formula

a=\dfrac{\dfrac{1}{2}mv^2}{\dfrac{1}{2}mr}

Put the value into the formula

a=\dfrac{6.2\times10^{6}\times1.6\times10^{-19}}{\dfrac{1}{2}\times1.67\times10^{-27}\times0.51}

a=2.32\times10^{15}\ m/s^2

We need to calculate the rate at which it emits energy because of its acceleration is

\dfrac{dE}{dt}=\dfrac{q^2a^2}{6\pi\epsilon_{0}c^3}

Put the value into the formula

\dfrac{dE}{dt}=\dfrac{(1.6\times10^{-19})^2\times(2.3\times10^{15})^2}{6\pi\times8.85\times10^{-12}\times(3\times10^{8})^3}

\dfrac{dE}{dt}=3.00\times10^{-23}\ J/s

The energy in ev/s

\dfrac{dE}{dt}=\dfrac{3.00\times10^{-23}}{1.6\times10^{-19}}\ J/s

\dfrac{dE}{dt}=1.875\times10^{-4}\ ev/s

We need to calculate the fraction of its energy that it radiates every second

\dfrac{\dfrac{dE}{dt}}{E}=\dfrac{1.875\times10^{-4}}{6.2\times10^{6}}

\dfrac{\dfrac{dE}{dt}}{E}=3.02\times10^{-11}

Hence, The fraction of its energy that it radiates every second is 3.02\times10^{-11}.

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ira [324]

Answer:

The current would stop

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3 0
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A truck travels to and from a stone quarry that is located 2.5 km to the east. What is the total distance traveled by the truck?
scoray [572]

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0

Explanation:

The question says the truck travelled to and fro from the stone quarry.

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3 years ago
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