A few of the positive particles aimed at a gold foil seemed to bounce back off of the thin metallic foil. so, the correct answer is option A.
<h3>What is the Rutherford experiment?</h3>
Rutherford performed an experiment in which alpha particles are bombarded on the gold foil.
Some of the particles bounced back which indicates that there are heavy particles present in the center of an atom.
Most alpha particles pass through the atom which indicates that there is a lot of empty space in an atom.
A few of the positive particles aimed at a gold foil seemed to bounce back off of the thin metallic foil. so, the correct answer is option A.
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Answer:
gluons
Explanation:
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4. Intermediate conductivity and a low melting point.
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Answer:
A λ = 97.23 nm
, B) λ = 486.2 nm
, C) λ = 53326 nm
Explanation:
With that problem let's use the Bohr model equation for the hydrogen atom
= -k e² /2a₀ 1/n²
For a transition between two states we have
-
= -k e² /2a₀ (1/
² - 1 / n₀²)
Now this energy is given by the Planck equation
E = h f
And the speed of light is
c = λ f
Let's replace
h c / λ = - k e² /2a₀ (1 /
² - 1 / no₀²)
1 / λ = - k e² /2a₀ hc (1 /
² -1 / n₀²)
Where the constants are the Rydberg constant
= 1.097 10⁷ m⁻¹
1 / λ =
(1 / n₀² - 1 / nf²)
Now we can substitute the given values
Part A
Initial state n₀ = 1 to the final state
= 4
1 / λ = 1.097 10⁷ (1/1 - 1/4²)
1 / λ = 1.0284 10⁷ m⁻¹
λ = 9.723 10⁻⁸ m
We reduce to nm
λ = 9.723 10⁻⁸ m (10⁹ nm / 1m)
λ = 97.23 nm
Part B
Initial state n₀ = 2 final state
= 4
1 / λ = 1.097 10⁷ (1/2² - 1/4²)
1 / λ = 0.2056 10⁻⁷ m
λ = 486.2 nm
Part C
Initial state n₀ = 3
1 / λ = 1,097 10⁷ (1/3² - 1/4²)
1 / λ = 5.3326 10⁵ m⁻¹
λ = 5.3326 10-5 m
λ = 53326 nm