The answer is 294j by puting it in kinetic energy formula.
its B 0.225kPa using the formula p=f/A then change the pascals into kpa
It's most likely the combination of a bucket and the wheel.
Answer: 40.84 m
Explanation:
Given
Radius of the disk, r = 2m
Velocity of the disk, v = 7 rad/s
Acceleration of the disk, α = 0.3 rad/s²
Here, we use the formula for kinematics of rotational motion to solve
2α(θ - θ•) = ω² - ω•²
Where,
ω• = 0
ω = v/r = 7/2
ω = 3.5 rad/s
2 * 0.3(θ - θ•) = 3.5² - 0
0.6(θ - θ•) = 12.25
(θ - θ•) = 12.25 / 0.6
(θ - θ•) = 20.42 rad
Since we have both the angle and it's radius, we can calculate the arc length
s = rθ = 2 * 20.42
s = 40.84 m
Thus, the needed distance is 40.84 m
Answer:
The x-component of the electric field at point P -- 31,638.41
Explanation:
Given data:
charge density 
Another charge density 
Electric field due to infinite sheet of charge is given as E
= 31,638.41
