Answer:
The concentration of NaOH solution is 3,65M
Explanation:
The neutralization of NaOH with HCl is:
NaOH + HCl → NaCl + H₂O
You are titrating 12,67 mL HCl 2,74M with your NaOH solution, the moles of HCl in the beaker are:
12,67 mL ≡ 0,01267L×
= <em>0,0347 moles HCl </em>≡ 0,0347 moles NaOH
The volume that you require for total neutralization of 12,67 mL HCl 2,74M is:
13,65 mL - 4,50 mL = <em>9,50 mL </em>≡ 0,0095L
Thus, the concentration of NaOH solution is:
= <em>3,65M</em>
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I hope it helps!
Copper ions, nitrate ions, and water is in the beaker
Answer:
0.100 M AlCl₃
Explanation:
The variation of boiling point by the addition of a nonvolatile solute is called ebullioscopy, and the temperature variation is calculated by:
ΔT = W.i
Where W = nsolute/msolvent, and i is the Van't Hoff factor. Because all the substances have the same molarity, n is equal for all of them.
i = final particles/initial particles
C₆H₁₂O₆ don't dissociate, so final particles = initial particles => i = 1;
AlCl₃ dissociates at Al⁺³ and 3Cl⁻, so has 4 final particles and 1 initial particle, i = 4/1 = 4;
NaCl dissociates at Na⁺ and Cl⁻ so has 2 final particles and 1 initial particle, i = 2/1 = 2;
MgCl₂ dissociates at Mg⁺² and 2Cl⁻, so has 3 final particles and 1 initial particle, i = 3/1 = 3.
So, the solution with AlCl₃ will have the highest ΔT, and because of that the highest boiling point.
Answer:
pH = 4
Explanation:
Step 1: Given data
Concentration of H⁺ ions in the solution ([H⁺]): 10⁻⁴ M
Step 2: Calculate the pH of the solution
We will use the definition of pH.
pH = -log [H⁺]
pH = -log 10⁻⁴ M
pH = 4
The pH of the solution is 4. Considering the pH scale, given the pH is lower than 7, the solution is acidic.
Answer:
1)
2) The dependent variable = The time it takes for one pendulum swing
3) The independent variable = The length of the pendulum string with weight at the bottom
Explanation:
The relationship between the length of the pendulum string and the time it takes for one pendulum swing is giving as follows;
Where;
T = The period of oscillation = The time to complete one oscillation =Two swings of the pendulum
L = The length of the pendulum
g = The acceleration due to gravity
Therefore, the time it takes for one pendulum swing is directly proportional to the square root of the length of the pendulum
The dependent variable = The time it takes for one pendulum swing
Th independent variable = The length of the pendulum string with weight at the bottom.
