There are two ingredients (A and B) that will be mixed in the reactor tank. Wait for READY signal to be on (when on, it signifie
s that QA Tank is ready for this batch). 2. To add the fixed amount of ingredient A to the mixing tank, VALVE_A needs to be on. To add the fixed amount of ingredient B to the mixing tank, VALVE_B needs to be on. Both VALVE_A and VALVE_B will be turned on for 10 seconds, then they need to be turned off automatically. 3. When material A is ready to be added, PULSE_A will be on. When material B is ready to be added, PULSE_B will be on. If the PULSE_A for material A (or PULSE_B for material B) is off, the material A cannot be added to the mixing tank even the VALVE_A is turned on. 4. After the materials are fed into the mixing tank, agitate and mix the materials at a high speed (500 rpm) by turning on the motor AGIT_ON_HS for 20 seconds. 5. After that, the agitate motor is then switch for a lower speed (200 rpm) by turning on the motor AGIT_ON_LS for 30 seconds.
1 answer:
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Answer:
Re=100,000⇒Q=275.25
Re=500,000⇒Q=1,757.77
Re=1,000,000⇒Q=3060.36
Explanation:
Given:
For air =25°C ,V=8 m/s
For surface =179°C
L=2.75 m ,b=3 m
We know that for flat plate
⇒Laminar flow
⇒Turbulent flow
<u> Take Re=100,000:</u>
So this is case of laminar flow
From standard air property table at 25°C
Pr= is 0.71 ,K=26.24
So
Nu=187.32 ()
187.32=
⇒h=1.78
heat transfer rate =h
=275.25
<u> Take Re=500,000:</u>
So this is case of turbulent flow
Nu=1196.18 ⇒h=11.14
heat transfer rate =h
=11.14(179-25)
= 1,757.77
<u> Take Re=1,000,000:</u>
So this is case of turbulent flow
Nu=2082.6 ⇒h=19.87
heat transfer rate =h
=19.87(179-25)
= 3060.36
Answer:
The volume of the extra water is
Solution:
As per the question:
Mass of the canoe,
Height of the canoe, h = 21.5 ft
Mass of the kevlar canoe,
Now, we know that, bouyant force equals the weight of the fluid displaced:
Now,
(1)
where
V = volume
= density
m = mass
Now, for the canoe,
Using eqn (1):
Similarly, for Kevlar canoe:
Now, for the excess volume:
V =
V =