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Free_Kalibri [48]
4 years ago
6

Identify one of the advantages of 3d modeling?

Engineering
1 answer:
Naddik [55]4 years ago
6 0

Answer:

Hello Adam here! (UWU)

Explanation:

The advantages of 3D modeling for designers is not limited to productivity and coordination, it is an excellent communication tool for both the designer and end user. 3D models can help spark important conversations during the design phase and potentially avoid costly construction mishaps.

Happy to Help! (>.O)

You might be interested in
A spherical balloon with a diameter of 9 m is filled with helium at 20°C and 200 kPa. Determine the mole number and the mass of
SIZIF [17.4K]

Answer:

<em>number of mole is 31342.36 moles</em>

<em>mass is 125.369 kg</em>

<em></em>

Explanation:

Diameter of the spherical balloon d = 9 m

radius r = d/2 = 9/2 = 4.5 m

The volume pf the sphere balloon ca be calculated from

V = \frac{4}{3} \pi r^3

V = \frac{4}{3}* 3.142* 4.5^3 = 381.75 m^3

Temperature of the gas T = 20 °C = 20 + 273 = 293 K

Pressure of the helium gas = 200 kPa = 200 x 10^3 Pa

number of moles n = ?

Using

PV = nRT

where

P is the pressure of the gas

V is the volume of the gas

n is the mole number of the gas

R is the gas constant = 8.314 m^3⋅Pa⋅K^−1⋅mol^−1

T is the temperature of the gas (must be converted to kelvin K)

substituting values, we have

200 x 10^3 x 381.75 = n x 8.314 x 293

number of moles n  = 76350000/2436 = <em>31342.36 moles</em>

We recall that n = m/MM

or m = n x MM

where

n is the number of moles

m is the mass of the gas

MM is the molar mass of the gas

For helium, the molar mass = 4 g/mol

substituting values, we have

m = 31342.36 x 4

m = 125369.44 g

m =<em> 125.369 kg</em>

3 0
3 years ago
Routers cannot be used to cut through material.<br><br> True<br> False
mario62 [17]

Answer:

Yes a router can be used to cut right through wood and sometimes it makes sense to do so. It leaves nice clean edges, can cut sharp curves and can follow a template

Explanation:

hope thats right

7 0
3 years ago
Read 2 more answers
Instructions: For each problem, identify the appropriate test statistic to be use (t test or z-test). Then compute z or t value.
Natalka [10]

The sample of 81 students was selected with a mean score of 90, this illustrates an example of a right tailed one sample z test.

<h3>How to illustrate the sample?</h3>

From the information given, the teacher claims that the mean score of students in his class is greater than 82 with a standard deviation of 20. In this case, the right tailed one sample z test is used.

The z value will be:

= (90 - 82)/20/✓81

= 3.6

Since 3.6 > 1.645, the null hypothesis will be rejected as there's enough evidence to support the teacher's claim.

When an online medicine shop claims that the mean delivery time for medicines is less than 120 minutes with a standard deviation of 30 minutes, the left tailed one sample test is used.

The z value will be:

= (100 - 120)/(30/✓49)

= -4.66

The null hypothesis is rejected as there is enough evidence to support the claim of the medicine shop.

Learn more about sampling on:

brainly.com/question/17831271

#SPJ1

6 0
2 years ago
In this homework problem we’ll begin completing an implementation of SimpleList that uses a linked list of Item objects internal
balu736 [363]

The solution contains multiple java files. The initial linked list is 10 20 30 40 . The modified list is 20 30 40

<u>Explanation</u>

//Define the interface SimpleList;

public interface SimpleList

{

   public Object get (int index);

   public void set (int index, Object element);

   public void add (int index, Object element);

   public Object remove(int index);

   public int size();

}

SimpleLinkedList.java:

//Define the class SimpleLinkedList that implements the SimpleList.

public class SimpleLinkedList implements SimpleList

{

   //Define the Item class.

   class Item

   {

       Object value;

       Item next;          

       Item (Object setValue, Item setNext)

       {

           value = setValue;

           next = setNext;

       }

   }      

   protected Item start;

   protected int currentSize;      

   //Define the default constructor.

   public SimpleLinkedList()

   {

       currentSize = 0;

       start = null;

   }      

   //Define the parameterized constructor.

   SimpleLinkedList(Object[] values)

   {

       currentSize = 0;          

       //Start the loop and call the add method.

       for(int i = 0; i<values.length;i++)

       {

           add(i, values[i]);

       }

   }      

   //Define the method to return the object

   // at the given index.

   atOverride

   public Object get (int index)

   {

       //Call the getItem() method and return it's value.

       return getItem(index).value;

   }      

   //Define the set() method.

   atOverride

   public void set (int index, Object element)

   {

       if (index < 0 || index >= currentSize)

       {

           return;

       }

       int currentIndex = 0;          

       for (Item current = start; current != null; current = current.next)

       {

           if (currentIndex == index)

           {

               current.value = element;

               break;

           }

           currentIndex++;

       }

   }    

   //Define the getItem() method.

   protected Item getItem(int index)

   {

       if (index < 0 || index >= currentSize)

       {

           return null;

       }      

       int currentIndex = 0;        

       for (Item current = start; current != null; current = current.next)

       {

           if (currentIndex == index)

           {

               return current;

           }

           currentIndex++;

       }

       return null;

   }      

   //Define the add() method.

   atOverride

   public void add (int index, Object toAdd)

   {

       if (index == 0)

       {

           start = new Item (toAdd, start);

           currentSize++;

           return;

       }        

       Item previousItem = getItem(index - 1);        

       if(previousItem == null)

       {

           return;

       }          

       Item newItem = new Item(toAdd, previousItem.next);

       previousItem.next = newItem;

       currentSize++;

   }      

   //Define the method to return the size of the linked list.

   atOverride

   public int size ()

   {

       return currentSize;

   }      

   //Define the method to remove an index from the linked list.

   atOverride

   public Object remove (int index) {

       // TODO Auto-generated method stub

       return null;

   }      

}

YourSimpleLinkedList.java:

//Define the YourSimpleLinkedList class.

public class YourSimpleLinkedList extends SimpleLinkedList

{

   //Define the default constructor.s

   public YourSimpleLinkedList()

   {

       super();

   }      

   //Define the parameterized constructor.

   YourSimpleLinkedList(Object[] values)

   {

       super(values);

   }

   //Define the method to remove an index.

   at Override

   public Object remove(int index)

   {

       //Return null if the index is out of range.

       if (index < 0 || index >= currentSize)

       {

           return null;

       }        

       //Set the start Item if the first value

       // is to be removed.

       if (index == 0)

       {

           //Store the value of the node to be removed.

           Object temp = start.value;

           

           //Set the start Item.

           start = start.next;

           

           //Update the size of the linked list and return

           // the deleted value.

           currentSize--;

           return temp;

       }        

       //Initialize the required variables.

       int currentIndex = 0;

       Item current = start;

       Item prev = start;        

       //Start the loop to traverse the list.

       while (current != null)

       {

           //Check the index value.

           if (currentIndex == index)

           {

               //Store the value to be deleted.

               Object temp = current.value;                

               //Set the next pointer.

               prev.next = current.next;                  

               //Update the size of the linked list and return

               // the deleted value.

               currentSize--;

               return temp;

           }            

           //Update the values.

           currentIndex++;

           prev = current;

           current = current.next;

       }

       return null;

   }

}

Main.java:

public class Main

{

   public static void main(String[] args)

   {

       //Create a list of objects.

       Object [] values = {10, 20, 30, 40};          

       //Create an object of the YourSimpleLinkedList class.

       YourSimpleLinkedList myList = new YourSimpleLinkedList(values);        

       //Display the initial list.

       System.out.print("The initial linked list is ");

       for (int i=0;i<myList.size();i++)

       {

           System.out.print(myList.get(i) + " ");

       }        

       //Remove an index from the list.

       myList.remove(0);        

       //Display the modified list.

       System.out.println();

       System.out.print("The modified list is ");

       for (int i=0;i<myList.size();i++)

       {

           System.out.print(myList.get(i) + " ");

       }

   }  

}

5 0
4 years ago
A fluid of density 900 kg/m3 passes through a converging section of an upstream diameter of 50 mm and a downstream diameter of 2
NISA [10]

Answer:

Q= 4.6 × 10⁻³ m³/s

actual velocity will be equal to 8.39 m/s

Explanation:

density of fluid = 900 kg/m³

d₁ = 0.025 m

d₂ = 0.05 m

Δ P = -40 k N/m²

C v = 0.89

using energy equation

\dfrac{P_1}{\gamma}+\dfrac{v_1^2}{2g} = \dfrac{P_2}{\gamma}+\dfrac{v_2^2}{2g}\\\dfrac{P_1-P_2}{\gamma}=\dfrac{v_2^2-v_1^2}{2g}\\\dfrac{-40\times 10^3\times 2}{900}=v_2^2-v_1^2

under ideal condition v₁² = 0

v₂² = 88.88

v₂ = 9.43 m/s

hence discharge at downstream will be

Q = Av

Q = \dfrac{\pi}{4}d_1^2 \times v

Q = \dfrac{\pi}{4}0.025^2 \times 9.43

Q= 4.6 × 10⁻³ m³/s

we know that

C_v =\dfrac{actual\ velocity}{theoretical\ velocity }\\0.89 =\dfrac{actual\ velocity}{9.43}\\actual\ velocity = 8.39m/s

hence , actual velocity will be equal to 8.39 m/s

6 0
3 years ago
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