Answer:
Explanation:
In Engineering and Physics a Phasor That is a portmanteau of phase vector, is a complex number that represents a sinusoidal function whose Amplitude (A), Angular Frequency (ω), and Initial Phase (θ) are Time-invariant.
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Loaded,
(s) =
=
is the loaded filter's transfer function.
A graded filter that, by virtue of its weight and permeability, stabilises the foot of an earth dam or other construction when it is installed at the base of that structure.
Air filters with depth loaded are made to achieve precisely that. They add particles gradually to create air passageways, reducing constriction. You may save time and money by using filters that last longer thanks to them. The bigger particles are caught at the filter's beginning, while the smaller particles are caught as it gets closer. This is intended to avoid rapid surface loading, hence facilitating more airflow. This enables longer-lasting filtration as well.
On the other hand, surface loading filters catch every particle that is on its surface. No matter how big or little the particles are, it doesn't care.
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Answer:
The impedance of the circuit depends on the angular frequency of the voltage source.
Explanation:
- In a electric circuit, the magnitude of the impedance, is given by the following expression:

where R = Resistance
Xl = Inductive reactance = ω*L
Xc = Capacitive Reactance = 1/ωC
and ω = angular frequency of the voltage source.
- So, it can be seen that the impedance depends on the value of the constants R,L and C, and on the angular frequency ω.
Answer:
El conocer la función del sistema nervioso permite comprender la estructura del cuerpo. Puesto que, toda acción que se se realice en ella dependerá del sistema nervioso para que sea eficaz
Answer:
the critical flaw length is 10.06 mm
Explanation:
Given the data in the question;
plane strain fracture toughness
= 92 Mpa√m
yield strength σ
= 900 Mpa
design stress is one-half of the yield strength ( 900 Mpa / 2 ) 450 Mpa
Y = 1.15
we know that;
Critical crack length
= 1/π(
/ Yσ )²
we substitute
= 1/π( 92 Mpa√m / (1.15 × 450 Mpa )²
= 1/π( 92 Mpa√m / (517.5 Mpa )²
= 1/π( 0.177777 )²
= 1/π( 0.03160466 )
= 0.01006 m = 10.06 mm
Therefore, the critical flaw length is 10.06 mm
{
= ( 10.06 mm ) > 3 mm
The critical flow is subject to detection