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NARA [144]
3 years ago
12

1. How did the change of stress (adding or removing reactants or products) cause a shift in the equilibrium system of your solut

ions? Use data to support your answer. Make sure you discuss all four stress changes: a. Adding a reactant b. Adding a product c. Removing a reactant d. Removing a product
Chemistry
2 answers:
tatyana61 [14]3 years ago
8 0

Answer:

<em><u>When additional reactant is added, the equilibrium shifts to reduce this stress: it makes more product. When additional product is added, the equilibrium shifts to reactants to reduce the stress. 2. Concentration is just one stress that can affect the equilibrium position.</u></em>

Explanation:

<h2>HOPE IT WILL HELP YOU✌✌✌✌✌</h2>
Charra [1.4K]3 years ago
7 0

Answer:

If reactant or product is removed, the equilibrium shifts to make more reactant or product, respectively, to make up for the loss.

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In a certain chemical reaction, 2 solid Mg atoms bond with O2 gas to produce solid
soldier1979 [14.2K]

Answer:

Option B. 2Mg(s) + O2 (g) —> 2MgO (s)

Explanation:

From the question given above,

We were told that:

2 solid Mg atoms bond with O2 gas to produce solid MgO.

This can be represented by an equation as follow:

2Mg(s) + O2 (g) —> MgO (s)

Next, we shall balance the above equation as follow:

2Mg(s) + O2 (g) —> MgO (s)

There are 2 atoms of Mg on the left side and 1 atom on the right side. It can be balance by putting 2 in front of MgO as shown below:

2Mg(s) + O2 (g) —> 2MgO (s)

Now, the equation is balanced.

8 0
4 years ago
What is the [h3o ] for a solution of seawater at 25°c that has a ph of 8.3?
Kipish [7]
PH of solution at 25ºC = 8.3

[ H_3O^+] = 10 ^{-pH}

{H_3O^+] = 10 ^{-8.3}

[H_3O^+] = 5.011*10^{-9}  M

hope this helps!
6 0
3 years ago
A 3.301 mass % aqueous solution of potassium hydroxide has a density of 1.05 g/mL. Calculate the molality of the solution. Give
8_murik_8 [283]

<u>Answer:</u> The molality of potassium hydroxide solution is 0.608 m

<u>Explanation:</u>

We are given:

3.301 mass % of potassium hydroxide solution.

This means that 3.301 grams of potassium hydroxide is present in 100 grams of solution

Mass of solvent = Mass of solution - Mass of solute (KOH)

Mass of solvent = (100 - 3.301) g = 96.699 g

To calculate the molality of solution, we use the equation:

\text{Molality}=\frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ (in grams})}

Where,

m_{solute} = Given mass of solute (KOH) = 3.301 g

M_{solute} = Molar mass of solute (KOH) = 56.1 g/mol

W_{solvent} = Mass of solvent = 96.699 g

Putting values in above equation, we get:

\text{Molality of KOH}=\frac{3.301\times 1000}{56.1\times 96.699}\\\\\text{Molality of KOH}=0.608m

Hence, the molality of potassium hydroxide solution is 0.608 m

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3 years ago
So anyone wanna be a Good Samaritan and help ya girl out
goldenfox [79]

The answer is JESUS BECAUSE HE IS ALWAYS THE ANSWER

8 0
3 years ago
How many moles are in 2.0 grams of Na?
lisov135 [29]

Answer:

46

Explanation:

Sodium metal has a molar mass of  

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