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Maru [420]
3 years ago
7

If an object possesses 500 J of potential energy, how much work is needed to lift this object?

Physics
1 answer:
ycow [4]3 years ago
3 0

Answer:

a) 500 J

Explanation:

Potential energy can be defined as an energy possessed by an object or body due to its position.

Mathematically, potential energy is given by the formula;

P.E = mgh

Where,

P.E represents potential energy measured in Joules.

m represents the mass of an object.

g represents acceleration due to gravity measured in meters per seconds square.

h represents the height measured in meters.

In Science, the potential energy possessed by an object or body is the same as the work done by the object or body.

Since we know that the object possessed 500 Joules of potential energy; it would ultimately require to do a work of 500 Joules to lift the object.

Mathematically, work done = force * distance

But force = mass * acceleration due to gravity

F = mg; d = h

Substituting into the work done formula, we have;

Hence, Workdone = Fd = mgh

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c)F_{net} = 0.640 kN

Explanation:

As we know that resultant force is the net force that is acting on the system

As per Newton's II law we know that net force is product of mass and acceleration

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F_{net} = ma

here we know

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for circular motion acceleration is given as

a_c = \frac{v^2}{R}

a_c = \frac{40^2}{200} = 8 m/s^2

now we have

F_{net} = 80 \times 8

F_{net} = 640 N

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Answer:

675J

Explanation:

Given parameters:

Force  = 45N

Distance  = 15m

Unknown:

Work done by Sheila  = ?

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         Work done  = Force x distance

 Now;

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\dot{m_{2}}=0.865 kg/s

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from steam tables , at 250 kPa, and at

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\dot{m_{1}}h_{1}+\dot{m_{2}}h_{2}=\dot{m_{3}}h_{3}

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