Explian the construction of electric motor?

A 120-meter-long ski ift carries skiers from a station at the foot of a slope to a second station 40 m above. what is the IMA (i

Pepsi [2]

The ideal mechanical advantage (IMA) of an inclined plane is given by:
$IMA = \frac{L}{h}$
where L is the length of the inclined plane while h is the height.
In our problem, L=120 m and h=40 m. Therefore, the IMA of the ski lift is
$IMA= \frac{120 m}{40 m}=3$

7 0

4 years ago

A small metal sphere has a mass of 0.16 g and a charge of -23.0 nC . It is 10 cm directly above an identical sphere with the sam

Hoochie [10]

Explanation:

A) we know that the magnitude of force

$F= \frac{kq_1q_2}{d^2}$

$F= \frac{9\times10^9\times23\times10^{-9}\times23\times10^{-9}}{0.1^2$

= 4.761×10^{-4} N

Also, net force = gravitational force - electrostatic force

B) F_net = F_g - F_e

m×a = m×g - 4.761×10^-4

a = g - 4.761×10^{-4}÷m

a= 9.8 - (4.761×10^{-4} /0.16×10^{-3})

a= 9.8 -2.975625

a= 6.82 m/s

8 0

3 years ago

Electric charge is distributed over the disk x2 + y2 ≤ 4 so that the charge density at (x, y) is rho(x, y) = 4x + 4y + 4x2 + 4y2

maw [93]

Answer:

Q=185.84C

Explanation:

We have to take into account the integral

$Q=\int \rho dV$

In this case we have a superficial density in coordinate system.

Hence, we have for R: x2 + y2 ≤ 4

$Q=\int_{-2}^2\int_{-\sqrt{4-x^2}}^{\sqrt{4-x^2}}\rho dydx$

but, for symmetry:

$Q=4\int_0^2\int_0^{\sqrt{4-x^2}}\rho dydx\\\\Q=4\int_0^2\int_0^{\sqrt{4-x^2}}(4x+4y+4x^2+4y^2) dydx\\\\Q=4\int_0^{2}[4x\sqrt{4-x^2}+2(4-x^2)+4x^2\sqrt{4-x^2}+\frac{4}{3}(4-x^2)^{3/2}]dx\\\\Q=4[46.46]=185.84C$