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liq [111]
3 years ago
14

Find the total amount due on a simple-interest loan if the principal is $3000 with a rate of 5% for 10 years.

Mathematics
1 answer:
Korolek [52]3 years ago
3 0
\bf \qquad \textit{Simple Interest Earned Amount}\\\\
A=P(1+rt)\qquad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to& \$3000\\
r=rate\to 5\%\to \frac{5}{100}\to &0.05\\
t=years\to &10
\end{cases}
\\\\\\
A=3000(1+0.05\cdot 10)\implies A=3000(1.5)
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Y=x+2<br> 3x+3y=6<br> solving systems by substitution
motikmotik

Answer:6

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x

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6

6

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6

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6

6

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6

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−

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6 0
3 years ago
What is the difference written in scientific notation? 0.00067 - 2.3 x 10^5
shepuryov [24]
0.00067=67X10^5 so

67X10^5-2.3X10^5

64.7X10^5 which can be expressed as:

6.47X10^6

(not sure if it matters to you or not, but technically we only had two significant figures so it should be rounded to 6.5X10^6)


5 0
3 years ago
Can you solve this for me
jenyasd209 [6]

The number in the blank box should be 44 because it said that "3 times x and 4 times y is 44".

You need to multiply the first equation by 3:

3x + 3y = 39.

Then, subtract the first equation from the second equation:

3x - 3x = 0

4y - 3y = y

44 - 39 = 5

Your new equation should look like this: y = 5

Now, substitute y = 5 into the first original equation:

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x = 8

Ans. (x, y) = (8, 5)

4 0
3 years ago
HELP AGAIN PLEASE I TRIED IT ON MY OWN AND FAILED :(
Alex787 [66]

Answer:  ∠ J = 62° , ∠ K = 59° , ∠ L = 59°

<u>Step-by-step explanation:</u>

It is given that it is an Isosceles Triangle, where L J ≅ K J

It follows that ∠ K ≅ ∠ L

         ⇒ 5x + 24 = 4x + 31

         ⇒   x + 24 =         31

         ⇒   x         =           7

Input the x-value into either equation to solve for  ∠ K &  ∠ L:

∠ K = 5x + 24

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      = 35 + 24

       = 59

∠ K ≅ ∠ L  ⇒   ∠ L = 59

Next, find the value of  ∠ J:

∠ J +  ∠ K +  ∠ L = 180    Triangle Sum Theorem

∠ J  +   59  +  59 = 180

∠ J          + 118     = 180

∠ J                       = 62

8 0
3 years ago
Find the simple interest on $8,000 at 4% interest for 2.5 years?
boyakko [2]

Answer:

800

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6 0
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