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Tanya [424]
3 years ago
6

How can you tell from the name the types of bonds present in a hydrocarbon?

Chemistry
2 answers:
Aneli [31]3 years ago
7 0

Answer:

Of bond is formed by sharing of electrons - covalent

If bond is formed by donation and by accepting electrons - ionic bond

Bond formed between metals - metallic bond.

Snezhnost [94]3 years ago
7 0

The name of a hydrocarbon dictates whether there are single C-C bonds, double C=C bonds, or triple C bonds. This is done by the name ending in -ane, -ene, and -yne. Let’s use common compound ‘methane’ as an example. Methane has a C-C bond because it ends in -ane. Methane is an alk-ANE. Methane has a C=C because it ends in -ene and is an alk-ENE. lastly, methyne has a triple C bond because it ends in -yne and is an alk-YNE.

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Which method preserves an image of a leaf?.
Sav [38]

Answer:

Tree sap flows over the leaf and preserves it.

Explanation:

Amber would preserve the image.

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3 years ago
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30. a. How do the properties of metals differ from those
Ahat [919]

Explanation:

Metals are elements that ionized by loss of electrons.

Ionic and molecular compounds are usually non-metals.

Properties of metals:

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  • None of the metal is soluble without a chemical change occurring.
  • They are ductile and malleable.
  • Metals are good conductor or heat and electricity in their free uncombined state.
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B. The specific property of metals accountable for their unusual electrical conductivity is due to the presence of free mobile electrons in their lattices.

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3 0
3 years ago
A nuclear fission reaction has mass difference between the products and the reactants of 0.0284 amu. Calculate the
notsponge [240]

Answer:

C) 4.24 x 10^{-12}

Explanation:

E = Δmc^{2}

Δm = 0.0284 x 1.66 x 10^{-27} kg = 4.714x10^{-29}kg

putting value in above equation

E = 4.714x10^{-29}kg x (3x10^{8})^{2} = 4.24 x 10^{-12}

6 0
3 years ago
Calculate the number of molecules present in 0.5 mole of water​
Aleksandr-060686 [28]

Explanation:

Mole = 0.5 = n/NA

n = no. of molecule

NA = avogadro number = 6.023x 10^23

so

N/NA = 0.5

N = 0.5 x 6.023 x 10^23

N = 3.0115 x 10^23

6 0
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Mariulka [41]

Answer:

4 answers

Explanation:

Do simple divison

7 0
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