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mamaluj [8]
3 years ago
5

The population size of panda

Chemistry
1 answer:
zhenek [66]3 years ago
7 0

Answer:

it will decrease because there will not be food for all of them and there is very little space for them now so if there is more they will start to fight

Explanation:

there is very little habitat left for panda bears so if there population increases the food and space with be filed

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What is the mass of solid NH4Cl formed when 75.5g of NH3 is mixed with an equal mass of HCl? What is the volume of the gas remai
taurus [48]

Answer:The volume of the remaining gas that is ammonia is 23.85 L.

Explanation:

NH_3(g)+HCl(g)\rightarrow NH_4Cl(s)

Moles of NH_3=\frac{\text{mass of} NH_3}{\text{Molar mass of}NH_3}=\frac{75.5 g}{17.03 g/mol}=4.43 mole

Moles of HCl of gas = \frac{\text{mass of} HCl}{\text{Molar mass of}HCl}=\frac{75.5 g}{36.5 g/mol}=2.06 mol

According to reaction 1 mole of HCl reacts with 1 mol of NH_3 then 2.06 moles of HCl will react with = 2.06 moles of NH_3

Moles left of ammonia left = 4.43 - 2.06 = 2.36 moles

Volume of the gas will be given by Ideal gas equation: PV=nRT

Pressure = 752 mmHg = 752 × 0.0031 atm = 2.33 atm

R = 0.08026 L atm/K mol

V = ? , n = number of moles of ammonia

Temperature = 14 °C = 14 + 273 K = 287 K(0°C = 273K)

V=\frac{2.36 mol\times 0.08206 L atm/K mol\times 287 K}{2.33 atm}=23.85 L

The volume of the remaining gas that is ammonia is 23.85 L.

8 0
3 years ago
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What is produced when an acid and an alkali react?
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To measure the volume of the blood system of an animal, the following experiment was done. A 1.0-mL sample of an aqueous solutio
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Answer:199mL

Explanation:

Let V ml be the volume of blood in animal.

When 1.0 ml sample is added, total volume becomes V+1.0ml. Its activity is 1000 dpm.

After equilibrium, 2.0 ml of the sample had activity of 10 dpm.

Hence, after equilibrium, the activity of V+1.0 ml of blood sample will be 10/2 (V+1.0ml)=1000dpm

Hence, V=199ml.

4 0
3 years ago
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