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mamaluj [8]
2 years ago
5

The population size of panda

Chemistry
1 answer:
zhenek [66]2 years ago
7 0

Answer:

it will decrease because there will not be food for all of them and there is very little space for them now so if there is more they will start to fight

Explanation:

there is very little habitat left for panda bears so if there population increases the food and space with be filed

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Which of the following fractions can be used in the conversion of 25 m3 to the unit cm3?
zaharov [31]

your answer would be C hope this helps

8 0
3 years ago
Iron fluoride (FeF2) dissociates according to the following equation:
melomori [17]

Answer:

S = 0.788 g/L

Explanation:

The solubility product (Kps) is an equilibrium solubization constant, which can be calculated by the equation:

Kps = \frac{[product]^x}{[reagent]^y}

Where x and y are the stoichiometric coefficients of the product and the reagent, respectively. Because of the aggregation form, the concentration of solids is always equal to 1 for use in this equation.

Analyzing the equation, we see that for 1 mol of Fe^{+2} is necessary 2 mols of F^-, so if we call "x" the molar concentration of Fe^2, for F^- we will have 2x, so:

Kps = [Fe^{+2}].[F^-]^2\\\\2.36x10^{-6} = x(2x)^2\\\\2.36x10^{-6} = 4x^3\\\\x^3 = 5.9x10^{-7}\\\\x = \sqrt[3]{5.9x10^{-7}} \\\\x = 8.4x10^{-3} mol/L

So, to calculate the solubility (S) of FeF2, which is in g/L, we multiply this concentration by the molar mass of FeF2, which is:

Fe = 55.8 g/mol

F = 19 g/mol

FeF2 = Fe + 2xF = 55.8 + 2x19 = 93.8 g/mol

So,

[tex]S = 8.4x10^{-3}x93.8

S = 0.788 g/L

4 0
3 years ago
There is nothing that you can do to conserve energy. True or False
Firdavs [7]
I am going to say it is false.
6 0
3 years ago
Read 2 more answers
An Erlenmeyer flask contains 25.00 mL of 0.10 M HCl. What is the pH of the solution?
max2010maxim [7]
C=0.10 mol/l

pH=-lg[H⁺]

HCl = H⁺ + Cl⁻

pH=-lgc

pH=-lg0.10=1.0

pH=1.0
4 0
3 years ago
Read 2 more answers
How much heat is gained when a 50.32g piece of aluminum is heated from 9.0°c to 16°c
Rashid [163]

Answer: 317 joules

Explanation:

The quantity of heat energy (Q) gained by aluminium depends on its Mass (M), specific heat capacity (C) and change in temperature (Φ)

Thus, Q = MCΦ

In this case,

Q = ?

Mass of aluminium = 50.32g

C = 0.90J/g°C

Φ = (Final temperature - Initial temperature)

= 16°C - 9°C = 7°C

Then, Q = MCΦ

Q = 50.32g x 0.90J/g°C x 7°C

Q = 317 joules

Thus, 317 joules of heat is gained.

5 0
3 years ago
Read 2 more answers
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