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3 years ago

When a neutrally charged atom loses an electron to another atom, the result is the creation of

1 answer:

5 0

When a neutrally charged atom loses an electron to another atom, the result is the creation of two ions (cation and anion).

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PLEASE HELP FELLOW BRAINLIEST I NEED YOU AND QUICK!!!!!!!!!!!!!!!!!!!!!!!! Thomas Jefferson was the first to suggest what practi

VashaNatasha [74]

Answer:

alternation of crops

Explanation:

Common legumes include clover, beans, peas, alfalfa, and peanuts. Thomas Jefferson suggested that farmers alternate their crops between different fields each year. They range from single cells up to large organisms measuring 50 centimeters or more.

5 0

2 years ago

Read 2 more answers

A 57.0 mL sample of a 0.120 M potassium sulfate solution is mixed with 35.5 mL of a 0.118 M lead(II) acetate solution and the fo

Katarina [22]

Answer:

Limiting reagent = lead(II) acetate

Theoretical yield = 1.2704 g

% yield = 78.09 %

Explanation:

Considering:

$Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}$

Or,

$Moles =Molarity \times {Volume\ of\ the\ solution}$

Given :

For potassium sulfate :

Molarity = 0.120 M

Volume = 57.0 mL

The conversion of mL to L is shown below:

1 mL = 10⁻³ L

Thus, volume = 57.0×10⁻³ L

Thus, moles of potassium sulfate:

$Moles=0.120 M \times {57.0\times 10^{-3}}\ moles$

Moles of potassium sulfate = 0.00684 moles

For lead(II) acetate :

Molarity = 0.118 M

Volume = 35.5 mL

The conversion of mL to L is shown below:

1 mL = 10⁻³ L

Thus, volume = 35.5×10⁻³ L

Thus, moles of lead(II) acetate :

$Moles=0.118 \times {35.5\times 10^{-3}}\ moles$

Moles of lead(II) acetate = 0.004189 moles

According to the given reaction:

$K_2SO_4_{(aq)}+Pb(C_2H_3O_2)_2_{(aq)}\rightarrow 2KC_2H_3O_2_{(s)}+PbSO_4_{(aq)}$

1 mole of potassium sulfate react with 1 mole of lead(II) acetate

0.00684 moles potassium sulfate react with 0.00684 mole of lead(II) acetate

Moles of lead(II) acetate = 0.004189 moles

Limiting reagent is the one which is present in small amount. Thus, lead(II) acetate is limiting reagent. ( 0.004189 < 0.00684)

The formation of the product is governed by the limiting reagent. So,

1 mole of lead(II) acetate gives 1 mole of lead(II) sulfate

0.004189 mole of lead(II) acetate gives 0.004189 mole of lead(II) sulfate

Molar mass of lead(II) sulfate = 303.26 g/mol

Mass of lead(II) sulfate = Moles × Molar mass = 0.004189 × 303.26 g = 1.2704 g

Theoretical yield = 1.2704 g

Given experimental yield = 0.992 g

<u>% yield = (Experimental yield / Theoretical yield) × 100 = (0.992/1.2704 g) × 100 = 78.09 %</u>

3 0

2 years ago

What is the mass sample of 0.0500 moles of zinc chloride ?

vlabodo [156]

Answer:

6.82g

0.59moles

Explanation:

1. What is the mass sample of 0.0500 moles of zinc chloride ?

Given parameters:

Number of moles ZnCl₂ = 0.05moles

Unknown:

Mass of the sample = ?

Solution:

To find the mass of a substance using the number of moles, it would be pertinent to understand what mole is.

A mole is a substance that contains the avogadro's number of particles.

It relates to the mass using the expression below;

Mass of a substance = number of moles x molar mass

Molar mass of ZnCl₂;

Atomic mass of Zn = 65.4g/mol

Cl = 35.5g/mol

Molar mass = 65.4 + 2(35.5) = 136.4g/mole

Mass of a substance = 0.05 x 136.4 = 6.82g

2. How many moles of potassium sulfide are in a 65.50g sample?

Given parameters:

Mass of K₂S = 65.5g

Unknown:

Number of moles = ?

Solution:

The number of moles of any substance is related to mass using the expression below;

Number of moles = $\frac{mass}{molar mass}$

Molar mass of K₂S = 2(39) + 32 = 110g/mol

Number of moles = $\frac{65.5}{110}$ = 0.59moles

8 0

3 years ago

Which of the following mixtures may be act as a buffer solution?

lions [1.4K]

Answer:

B) HF, NaF

Explanation:

A buffer solution is made up of a weak acid and its conjugate base.
In this case, HF is a weak acid and NaF is the conjugate base, therefore the mixture of HF, and NaF would make a perfect buffer solution.
The buffer would have the weak acid HF and its conjugate base, F- which comes from the soluble salt NaF.

4 0

3 years ago

8. How much heat is released when 85.0 g of steam condense to liquid water?

sergeinik [125]

Answer:

199920J

Explanation:

Given parameters:

Mass of steam = 85g

Unknown:

Heat released when the liquid is condensed = ?

Solution:

The heat released by the substance is given as;

H = mL

H is the heat released

m is the mass

L is the latent heat of steam = 2352J/g

Heat released = 85 x 2352 = 199920J

3 0

3 years ago