Question

33. How many atoms are present in 49.3 L of gaseous carbon tetrachloride at STP.

Answer 1

Answer:

1.32 x 10²⁴

Explanation:

Given parameters:

Volume of carbon tetrachloride  = 49.3L

Unknown:

Number of atoms at STP  = ?

Solution:

To solve this problem;

At STP;

     1 mole of a substance occupies 22.4L ;

 So;

       Let us find the number of moles;

               22.4L    = 1 mole

             49.3L will give $\frac{49.3}{22.4}$   = 2.2mole

So;

             1 mole of substance contains 6.02 x 10²³ atoms

           2.2 mole of Carbon tetrachloride  = 2.2 x 6.02 x 10²³ = 1.32 x 10²⁴