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-BARSIC- [3]
3 years ago
15

33. How many atoms are present in 49.3 L of gaseous carbon tetrachloride at STP.

Chemistry
1 answer:
Marina86 [1]3 years ago
3 0

Answer:

1.32 x 10²⁴

Explanation:

Given parameters:

Volume of carbon tetrachloride  = 49.3L

Unknown:

Number of atoms at STP  = ?

Solution:

To solve this problem;

At STP;

     1 mole of a substance occupies 22.4L ;

 So;

       Let us find the number of moles;

               22.4L    = 1 mole

             49.3L will give \frac{49.3}{22.4}   = 2.2mole

So;

             1 mole of substance contains 6.02 x 10²³ atoms

           2.2 mole of Carbon tetrachloride  = 2.2 x 6.02 x 10²³ = 1.32 x 10²⁴

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