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Iteru [2.4K]
3 years ago
8

How much energy is required to raise the temperature of 0.2 kg of aluminum

Chemistry
1 answer:
Ann [662]3 years ago
3 0
B. 538 j hoped this helps
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You want to know how many moles of gas your lungs can hold. You start off with a balloon that has 1.4 moles of gas and occupies
Mrrafil [7]

Number of moles : n₂ = 1.775 moles

<h3>Further explanation</h3>

Given

Moles = n₁ = 1.4

Volume = V₁=22.4 L

V₂=28.4 L

Required

Moles-n₂

Solution

Avogadro's hypothesis, at the same temperature and pressure, the ratio of gas volume will be equal to the ratio of gas moles  

The ratio of gas volume will be equal to the ratio of gas moles

\tt \dfrac{V_1}{V_2}=\dfrac{n_1}{n_2}

Input the values :

n₂ = (V₂ x n₁)/V₁

n₂ = (28.4 x 1.4)/22.4

n₂ = 1.775 moles

4 0
3 years ago
Does the statement describe a scientific law?
ale4655 [162]

Answer:

I think it's C sorry if I am wrong

8 0
2 years ago
If element x forms the oxides xo and x2o3 the oxidation numbers of element x are
Deffense [45]

Answer:

b) +2 and +3.

Explanation:

Hello,

In this case, given the molecular formulas:

XO

And:

X_2O_3

We can relate the subscripts with the oxidation states by knowing that they are crossed when the compound is formed, for that reason, we notice that oxygen oxidation state should be -2 for both cases and the oxidation state of X in the first formula must be +2 since both X and O has one as their subscript as they were simplified:

X^{+2}O^{-2}

Moreover, for the second case the oxidation state of X should be +3 in order to obtain 3 as the subscript of oxygen:

X_2^{+3}O_3^{-2}

Thus, answer is b)+2 and +3

Best regards.

3 0
3 years ago
Pls help!!!!!
erica [24]

Answer:

moving i think! Hope this helps

Explanation:

3 0
3 years ago
Read 2 more answers
Calculate the atomic mass of lead. The four lead isotopes have atomic masses and relative abundances of 203.973 amu (1.4%), 205.
blondinia [14]
207.217 amu
Work:
203.973 amu *(0.014) = 2.855 amu
205.974 amu *(0.241) = 49.639 amu
206.976 amu *(0.221) = 45.741 amu
207.977 amu *(0.524) = 108.979 amu

2.855 + 49.639 + 45.741 + 108.979 = 207.217 amu
8 0
3 years ago
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