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HACTEHA [7]
3 years ago
11

The balanced chemical equation below represents the formation of magnesium chloride.

Chemistry
1 answer:
Novay_Z [31]3 years ago
7 0

Answer:

C. 33.6L

Explanation:

Based on the reaction, 2 moles of HCl reacts producing 1 mole of hydrogen.

To solve this question we must find the moles of hydrogen produced using the reaction. Then, with combined gas law (PV = nRT) we can find the volume produced:

<em>Moles H2:</em>

3.00 moles HCl * (1mol H2 / 2mol HCl) = 1.50 moles H2 are produced

<em>Volume:</em>

PV = nRT

V = nRT / P

<em>Where P is pressure = 1atm at STP</em>

<em>V is volume = Our incognite</em>

<em>n are moles of the gas = 1.50 moles</em>

<em>R is gas constant = 0.082atmL/molK</em>

<em>T is absolute temperature = 273.15K</em>

<em />

V = nRT / P

V = 1.50mol*0.082atmL/molK*273.15K / 1atm

V = 33.6L

<h3>C. 33.6L</h3>
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Answer:

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Astudent prepareda calibration curve by plotting absorbance of the standards against the [FeSCN2+] molar concentration (M). The
Nuetrik [128]

Answer:

Explanation:

Chemistry 1B Experiment 7

1-3 5.0 1.5 3.5

Part 2: Determining the equilibrium constant.

Label 5 medium-sized test tubes. Table 7.2 shows the amounts of 2.00 × 10–3

M

Fe(NO3)3 (in 1 M HNO3) solution, 2.00 × 10–3

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each tube. (Record the exact amount of each solution that you actually add. You will

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Obtain five separate small pieces of parafilm. Close the top of each test tube with

the parafilm. Mix each solution thoroughly by inverting the test tube several times.

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Measure and record the absorbance of each solution at the 447 nm.

Table 7.2 Composition of solutions for determining the equilibrium constant.

Test Tube

Volume of

2.00 × 10–3

M Fe(NO3)3

in 1 M HNO3 (mL)

Volume of

2.00 × 10–3

M KSCN

(mL)

Volume of

purified water

(mL)

2-1 5.0 1.0 4.0

2-2 5.0 2.0 3.0

2-3 5.0 3.0 2.0

2-4 5.0 4.0 1.0

2-5 5.0 5.0 none

Calculations

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Assuming that “all” of the SCN–

ions have been converted to FeSCN2+ ions,

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Because of the 1:1 stoichiometry, that initial concentration of SCN– is equal to

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