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3 years ago

12

______ tides, tides that are weaker than normal, happen when the Moon is at first or last quarter phase and the sun and moon int

erfere with each other.
A high
B low
C neap
D spring

2 answers:

katrin2010 [14]3 years ago

4 0

Answer:

C. Neap Tides

Explanation:

MAXImum [283]3 years ago

4 0

Answer:

c neap tides

Explanation:

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Waves that make up the visible part of the electromagnetic spectrum have

tamaranim1 [39]

Lower energy than x rays

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3 years ago

An example of an action and reaction is sitting on a chair. Your body pushes down on the chair because of the force of what?

vaieri [72.5K]

Your body is pushing down on a chair because it is being attracted by gravity, the reason that your body is not moving down because there is a normal force acting on your body; together the net force of weight (m*g) and normal force is equal to zero

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3 years ago

Your own car has a mass of 2000 kg. If your car produces a force of 5000 N, how fast will it accelerate?

Sidana [21]

Answer:

2.5m/s²

Explanation:

Given parameters:

Mass of car = 2000kg

Force produced by the car = 5000N

Unknown:

Acceleration of the car = ?

Solution:

According to Newton's second law of motion, Force is a product of mass and acceleration.

Force = mass x acceleration

Now, insert the parameters and find the unknown;

5000 = 2000 x acceleration

Acceleration = $\frac{5000}{2000}$ = 2.5m/s²

7 0

3 years ago

A basketball has a mass of 601 g. Moving to the right and heading downward at an angle of 29 degree to the vertical, it hits the

olga55 [171]

Answer:

Change in momentum, $\Delta p=6.3\ kg-m/s$

Explanation:

It is given that,

Mass of the basketball, m = 601 g = 0.601 kg

The basketball makes an angle of 29 degrees to the vertical, it hits the floor with a speed, v = 6 m/s

It bounces up with the same speed, again moving to the right at an angle of 29 degree to the vertical. We need to find the change in momentum. It is given by :

$\Delta p=mv\ cos\theta-(-mv\ cos\theta)$

$\Delta p=2mv\ cos\theta$

$\Delta p=2\times 0.601\times 6\times \ cos(29)$

$\Delta p=6.3\ kg-m/s$

So, the change in momentum of the basketball is 6.3 kg-m/s. Hence, this is the required solution.

6 0

4 years ago

g A lighter ball A with momentum PA=5.0 kg∙m/s in positive x-direction approaches a heavier ball B at rest before the collision.

Svet_ta [14]

Answer:

7kgm/s

Explanation:

Using the law of conservation of momentum which states that the sum of momentum of bodies before collision is equal to the sum of the bodies after collision.

Let P1A and P1B be the initial momentum of the bodies A and B respectively

Let P2A and P2B be the final momentum of the bodies A and B respectively after collision.

Based on the law:

P1A+P2A = P1B + P2B

Given P1A = 5kgm/s

P2A = 0kgm/s(ball B at rest before collision)

P2A = -2.0kgm/s (negative because it moves in the negative x direction)

P2B = ?

Substituting the values in the equation gives;

5+0 = -2+P2B

5+2 = P2B

P2B = 7kgm/s

3 0

3 years ago