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REY [17]
3 years ago
12

______ tides, tides that are weaker than normal, happen when the Moon is at first or last quarter phase and the sun and moon int

erfere with each other.
A high
B low
C neap
D spring
Physics
2 answers:
katrin2010 [14]3 years ago
4 0

Answer:

C. Neap Tides

Explanation:

MAXImum [283]3 years ago
4 0

Answer:

c neap tides

Explanation:

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Once a well has reached the water table, it will not run dry true or false? -earth science
prohojiy [21]
No, this is false.

In principle, every well can run dry, and this includes a well that has reached the water table. If the water is taken from the well faster than it's replenishing itself, the well will run dry- and in this situation, typically people need to look for a new place to have a well.
3 0
4 years ago
Read 2 more answers
A circuit contains a 1.5v battery and a bulb with a 3 ohms resistance, calculate the current of the circuit
alexandr1967 [171]

Answer: 0.5ampere

Explanation:V=IR

Where v=voltage

I=current and

R= resistance

Therefore, I=V/R = 1.5/3

= 0.5ampere

5 0
4 years ago
"A problem involves a car of mass m going down a track from a height H, and round a loop of radius r. The loop is frictionless.
neonofarm [45]

Answer:

Explanation:

At the topmost position,  the car does not have zero velocity but it has velocity of v so that

v² /r = g or centripetal acceleration should be equal to g ( 9.8 )

Considering that,  the car must fall from a height of 2r + h where

mgh = 1/2 mv²

= 1/2 m gr

So h = r/2

Hence the ball must fall from a height of

2r + r /2

= 2.5 r . So that it can provide velocity of v  at the top where

v² / r = g .

4 0
3 years ago
if a ball on a string swung in a circles and string suddenly breaks.the ball will move into what direction?
horrorfan [7]

Answer:

The ball will swing in the direction it was going once the string breaks.

Explanation:

8 0
3 years ago
A fillet weld has a cross-sectional area of 25.0 mm2and is 300 mm long. (a) What quantity of heat (in joules) is required to acc
HACTEHA [7]

Answer:

77362.56 J

163730.28571 J

Explanation:

A = Area = 25 mm²

l = Length = 300 mm

K = Constant = 3.33\times 10^{-6}

\eta = Heat transfer factor = 0.75

f_m = Melting factor = 0.63

T = Melting point of low carbon steel = 1760 K

Volume of the fillet would be

V=Al\\\Rightarrow V=25\times 300\\\Rightarrow V=7500\ mm^3=7500\times 10^{-9}\ m^3

The unit energy for melting is given by

U_m=KT^2\\\Rightarrow U_m=3.33\times 10^{-6}\times 1760^2\\\Rightarrow U_m=10.315008\ J/mm^3

Heat would be

Q=U_mV\\\Rightarrow Q=10.315008\times 7500\\\Rightarrow Q=77362.56\ J

Heat required to weld is 77362.56 J

Amount of heat generation is given by

Q_g=\dfrac{Q}{\eta f_m}\\\Rightarrow Q_g=\dfrac{77362.56}{0.75\times 0.63}\\\Rightarrow Q_g=163730.28571\ J

The heat generated at the welding source is 163730.28571 J

7 0
4 years ago
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