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Anna71 [15]
3 years ago
5

A jet airplane is in level flight. The mass of the airplane is m=8930 kg. The airplane travels at a constant speed around a circ

ular path of radius ????=8.23 mi and makes one revolution every T=0.109 h. Given that the lift force acts perpendicularly upward from the plane defined by the wings, what is the magnitude of the lift force acting on the airplane?
Physics
1 answer:
Doss [256]3 years ago
6 0

Answer:88.95 kN

Explanation:

Given

mass of Plane =8930 kg

radius of circular path =8.23 mi\approx 13244.9 m

Time period =0.109 h

Let F be the lift force

If Plane is making an \theta with horizontal then F will make an angle of 90-\theta w.r.t horizontal

Thus

Fcos\theta =mg---1

Fsin\theta =m\omega ^2r------2

and \omegais given by

\omega =\frac{2\pi }{T}=\frac{2\times 3.142}{392.4}=0.0160 rad/s

Divide 2 & 1

tan\theta =\frac{\omega ^2r}{g}

tan\theta =\frac{0.0160^2\times 13244.9}{9.8}

tan\theta =0.345

\theta =19.03

Substitute \thetain 1

Fcos(19.03)=8930\times 9.8

F=88.95 kN

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