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umka21 [38]
3 years ago
13

How many (s) sublevels are present in calcium atom (Ca)?

Chemistry
1 answer:
Arlecino [84]3 years ago
6 0

Answer:

nineteen atoms

Explanation:

nineteen atoms

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What best explains the type of energy present in the vibrating atoms of a substance? It is thermal energy, which is a type of ki
natima [27]

What best explains the type of energy present in the vibrating atoms of a substance?

The answer is: <u>It is thermal energy, which is a type of kinetic energy. </u>

5 0
3 years ago
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What is the molar mass of barium hydroxide
maksim [4K]

Answer:

171.34 g/mol

Explanation:

Ba molar mass = 137.328 g/mol

O molar mass = 15.999 g/mol * 2 = 31.9980 g/mol

H molar mass = 1.008 g/mol * 2 = 2.0160 g/mol

137.328 + 31.9980 + 2.0160 = 171.3420 = 171.34 g/mol

4 0
3 years ago
A substance releases heat when it changes from
slega [8]
The answer should be (A) liquid to solid. This is because it releases the heat absorbed by it when it had changed into liquid.
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4 years ago
Frank has a sample of steel that weighs 80 grams. If the density of his sample of steel is 8 g/cm3, what is the sample’s volume?
IRINA_888 [86]
Density (p) is defined as the mass (m) per unit volume (v) or:

p = m/v 

Using this relationship, the volume is:

v = m/p

Using the given values of mass of 80 grams and density of 8 g/cm3, the sample volume is:

v = 80 grams/8 grams/cm3
v = 10 cm3

The final answer is 10 cm3.
7 0
4 years ago
A 115.0-g sample of oxygen was produced by heating 400.0 g of potassium chlorate.2KClO3 Right arrow. 2KCI + 3O2What is the perce
STALIN [3.7K]

Answer:

73.4% is the percent yield

Explanation:

2KClO₃ →  2KCl  + 3O₂

This is a decomposition reaction, where 2 moles of potassium chlorate decompose to 2 moles of potassium chloride and 3 moles of oxygen.

We determine the moles of salt: 400 g . 1. mol /122.5g= 3.26 moles of KClO₃

In the theoretical yield of the reaction we say:

2 moles of potassium chlorate can produce 3 moles of oxygen

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The mass of produced oxygen is: 4.89 mol . 32 g /1mol = 156.6g

But, we have produced 115 g. Let's determine the percent yield of reaction

Percent yield = (Produced yield/Theoretical yield) . 100

(115g / 156.6g) . 100 = 73.4 %

5 0
3 years ago
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