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olga55 [171]
2 years ago
5

What are the like fractions of 1/2 and 3/7

Mathematics
1 answer:
Step2247 [10]2 years ago
8 0

Answer:

7/14 and 6/14

Step-by-step explanation:

we are trying to find the same denominator for the 2 fractons, so 1/2 times 2 to both sides would be 7/14. and 3/7 times 2 to both sides would be 6/14. (same denominator)

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Help please? It’s math.
Umnica [9.8K]
Answer:
X = 7/5
when the value of x is 7/5 the equation will be true
Step-by-step explanation:
To fine the value of x that makes the equation true, we equate the expression to zero to find the value of x.
Check attachment for processes
Therefore when the value of x is 7/5 the equation will be true
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3 years ago
Find the derivative of f(t)=2√t - 2/√t
Semmy [17]
The answer is t=1.

Hope this helps.
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Read 2 more answers
What are 6 whole numbers -3.5 and 5.5
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3 0
2 years ago
Which one of the following graphs is the graph of:3if -2 < x < 01if x = 0if 0 < x≤ 2f(x) =A.44B.4-²-(x + 1)?
In-s [12.5K]

Given the piecewise function:

f(x)=\begin{cases}{3\text{ if -2}\leq x

Let's select the graph which represents the function.

We have the graph below:

For f(x) = 3, the graph will be a horizontal line on y = 3 which has an open dot on x = 0 and a closed dot on x = -2

For f(x) = 1 if x = 0, the graph will have a closed dot located on the point (0, 1)

For f(x) = -(x + 1) if 0 < x ≤2, the graph will have a negative slope with an open dot on (0, -1) and closed dot on (2, -3)

ANSWER:

Graph B

8 0
1 year ago
[10 points] A manufacturer wants to design an open box having a square base and a surface area of 108 square inches. What dimens
MissTica

Answer:

  6 inches square by 3 inches high

Step-by-step explanation:

For a given surface area, the volume of an open-top box is maximized when it has the shape of half a cube. If the area were than of the whole cube, it would be 216 in² = 6×36 in².

That is, the bottom is 6 inches square, and the sides are 3 inches high.

_____

Let x and h represent the base edge length and box height, respectively. Then we have ...

  x² +4xh = 108 . . . . box surface area

Solving for height, we get ...

  h = (108 -x²)/(4x) = 27/x -x/4

The volume is the product of base area and height, so is ...

  V = x²h = x²(27/x -x/4) = 27x -x³/4

We want to maximize the volume, so we want to set its derivative to zero.

  dV/dx = 0 = 27 -(3/4)x²

  x² = (4/3)(27) = 36

  x = 6

  h = 108/x² = 3

The box is 6 inches square and 3 inches high.

_____

<em>Comment on maximum volume, minimum area</em>

In the general case of<em> an open-top box</em>, the volume is maximized when the cost of the bottom and the cost of each pair of opposite sides is the same. Here, the "cost" is simply the area, so the area of the bottom is 1/3 the total area, 36 in².

If the box has a <em>closed top</em>, then each pair of opposite sides will have the same cost for a maximum-volume box. If costs are uniform, the box is a cube.

7 0
2 years ago
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