Answer:
1.45
Explanation:
Refractive index of the liquid is given as;
Refractive index =
But,
speed =
Since a certain light of specific wavelength was used during the same time, let the time be represented by t.
So that;
speed of light in vacuum =
speed of light in the liquid =
Refractive index = ÷
= x
Refractive index =
= 1.4536
= 1.45
The refractive index of the liquid is 1.45.
Answer:
A. Attractive
B. ( μ₀I² ) / ( 2πd )
Explanation:
A. We know that currents in the same direction attract, and currents in the opposite direction repel, according to ampere's law. In this case the current in the two wires are flowing in the same direction, and hence the force between the two wires are attractive.
B. Suppose that two wires of length and both carry the current in the same direction ( given ). In the presence of a magnetic field produced by wire 1, a force of magnitude m say, is experienced by wire 2. The magnitude of the magnetic field produced by wire 1 at distance say d, from it's axis, should thus be the following -
= μ₀I / 2πd
The force experienced by wire 2 should thus be -
= I( )
= I Sin( 90 )
= I ( μ₀I / 2πd )
Therefore the force per unit length experienced by wire 2 toward wire 1 should be ...
( / ) = ( μ₀I² ) / ( 2πd ) ... which is our solution
To solve this problem we must first find the potential on the body which is given as a product between the number of turns, the area and the variation of the magnetic field as a function of time. Once the potential is found, we will apply Ohm's Law with which we can find the induced current on the body. Our values are,
a) The magnitude of average induced emf is given by
Here N =1
b) The magnitude of the induced current is
Here Resistance is
Therefore the induced current is 0.00108A