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Delvig [45]
3 years ago
11

Pyruvate is the end product of glycolysis. Its further metabolism depends on the organism and on the presence or absence of oxyg

en. Draw the structure of the product from each reaction as it would exist at pH 7. Include the appropriate hydrogen atoms. Reaction A: aerobic conditions in humans or yeast

Chemistry
1 answer:
murzikaleks [220]3 years ago
5 0

The given question is incomplete. The image present in the question for Reaction A is attached below along with the answer.

Explanation:

Pyruvate molecule reacts with Coenzyme A in the presence of oxygen and it results in the formation of acetyl Coenzyme A and carbon dioxide.

The enzyme pyruvae dehydrogenase helps in catalyzing this reaction. As in this biochemical reaction NAD^{+} gets converted into NADH.

This reaction is shown in the image attached below.  

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What is the mass of 2.50 moles of NaCl
garik1379 [7]

Answer:

The mass of 2,50 moles of NaCl is 146, 25 g.

Explanation:

First we calculate the mass of 1 mol of NaCl, starting from the atomic weights of Na and Cl obtained from the periodic table. Then we calculate the mass of 2.50 moles of compound, making a simple rule of three:

Weight NaCl= Weight Na + Weight Cl=  23 g+ 35,5 g= 58, 5 g/ mol

1 mol ------ 58, 5 g

2,5 mol---x= (2,5 mol x 58, 5 g)/ 1 mol = <u>146, 25 g</u>

8 0
3 years ago
If 12.5 grams of strontium hydroxide is reacted with 150 mL of 3.5 M carbonic acid, identify the limiting reactant.
vesna_86 [32]

Answer:

Sr(OH)2

Explanation:

We'll begin by calculating the number of mole of carbonic acid in 150mL of 3.5 M carbonic acid solution. This is illustrated below:

Molarity = 3.5M

Volume = 150mL = 150/1000 = 0.15L

Mole of carbonic acid, H2CO3 =..?

Mole = Molarity x Volume

Mole of carbonic acid, H2CO3 = 3.5 x 0.15 = 0.525 mole.

Next, we shall convert 0.525 mole of carbonic acid, H2CO3 to grams.

Mole of H2CO3 = 0.525 mole

Molar mass of H2CO3 = (2x1) + 12 + (16x3) = 62g/mol.

Mass of H2CO3 =..?

Mass = mole x molar mass

Mass of H2CO3 = 0.525 x 62 = 32.55g

Next, we shall write the balanced equation for the reaction. This is given below:

Sr(OH)2 + H2CO3 → SrCO3 + 2H2O

Next, we shall determine the mass of Sr(OH)2 and H2CO3 that reacted from the balanced equation. This is illustrated below:

Molar mass of Sr(OH)2 = 88 + 2(16 + 1) = 88 + 2(17) = 122g/mol

Mass of Sr(OH)2 from the balanced equation = 1 x 122 = 122g

Molar mass of H2CO3 = (2x1) + 12 + (16x3) = 62g/mol.

Mass of H2CO3 from the balanced equation = 1 x 62 = 62g.

From the balanced equation above, 122g of Sr(OH)2 reacted with 62g of H2CO3.

Finally, we shall determine the limiting reactant as follow:

From the balanced equation above, 122g of Sr(OH)2 reacted with 62g of H2CO3.

Therefore, 12.5g of Sr(OH)2 will react with = (12.5 x 62)/122 = 6.35g.

We can see evidently from the calculations made above that it will take 6.35g out 32.55g of H2CO3 to react with 12.5g of Sr(OH)2. Therefore, Sr(OH)2 is the limiting reactant and H2CO3 is the excess reactant

5 0
3 years ago
Read 2 more answers
Even if you don't touch a marshmallow to a campfire flame, holding a marshmallow near a flame causes it to toast and turn brown.
Olin [163]
Heat radiates from the fire and cooks the marshmallow because heat transfer.
6 0
2 years ago
Read 2 more answers
What do you think about chemistry? define chemistry of the past ?​
Shalnov [3]

Answer: Most people think positively about chemistry. Chemistry has had a good impact on the world, such as the impact of renewable energy, clean water, and technology.

Explanation:

Hope this was helpful :)

5 0
2 years ago
Lavoisier made an important contribution to chemistry by _____.
Harlamova29_29 [7]

Answer:

Lavoisier made an important contribution to chemistry by the law of conservation of mass

Explanation:

The law of conservation of mass tell us, that the mass doens't change in a system. You have the same mass at the begining and in the end of a reaction.

Matter is neither created, nor destroyed in a chemical reaction.

This law also states that mass of reactants is the same of products in any chemical reaction

6 0
2 years ago
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