Answer:
Mass of ethanol obtained is 260.682 grams.
Volume of the ethanol obtained is 0.3304 L.
Explanation:

Moles of glucose = 
According to the reaction, 1 mol of gluocse gives 2 moles of ethanol.
Then 2.833 moles of glucose will give :

Mass of 5.667 moles of an ethanol :
5.667 mol × 46 g/mol = 260.682 g
Volume of ethanol = V
Density of the ethanol = 0.789 g/mL



Mass of ethanol obtained is 260.682 grams.
Volume of the ethanol obtained is 0.3304 L.
False the opposite should happen!
Atomic mass Ca = 40.078 a.m.u
40.078 g -------------------- 6.02x10²³ atoms
72.8 g ---------------------- ??
72.8 x ( 6.02x10²³) / 40.078 =
4.38x10²⁵ / 40.078 = 1.093x10²⁴ atoms
hope this helps!