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Lelechka [254]
3 years ago
11

To begin, check that Reaction 1 and Forward are selected. In this reaction, hydrogen (H2) and oxygen (O2) react to form water (H

2O). The reaction takes place inside a device called a calorimeter. Inside the calorimeter, a small chamber holds the reactants. The rest of the calorimeter is filled with water. Click Play (). What happens?
Chemistry
1 answer:
Kruka [31]3 years ago
3 0

Answer:

The reaction occurs and all H2 and O2 unite to form H20

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Pls help will give brainiest
kozerog [31]

Answer: A

Explanation:

4 0
3 years ago
Read 2 more answers
if a molecule of carbon dioxide is involved in a chemical reaction, how is it represented in the chemical equation for the react
DIA [1.3K]
Im mot sure but you could ask my mum
4 0
3 years ago
Why does the dilution equation, M 1 V 1 = M 2 V 2, work?
valentina_108 [34]

Answer:

d) The dilution equation works because the number of moles remains the same.

Explanation:

Let’s say that you have 1 mol of a solute in I L of solution. The concentration is 1 mol·L⁻¹. and <em>M</em>₁<em>V</em>₁ = 1 mol.

Now, you dilute the solution to a volume of 2 L. You still have 1 mol of solute, but in 2 L of solution. The new concentration is 0.5 mol·L⁻¹.

The volume has doubled, but the volume has halved, and <em>M</em>₂<em>V</em>₂ = 1 mol.

b) <em>Wrong</em>. The molar concentration changes on dilution.

c) <em>Wrong</em>. The volume changes on dilution.

a) <em>Wrong</em>, although technically correct, because if the moles don’t change, the mass doesn’t change either. However, the formula <em>M</em>₁<em>V</em>₁ has units mol·L⁻¹ × L = mol. Thus, in the formula, it is moles that are constant.

6 0
4 years ago
Read 2 more answers
Equation balancing a. S(s) + O2(g) → SO3(8) b. 2Al(s) + 3C12(8) ► 2AICI,(s) E. 2NaOH(s) + H2SO,(ac) —Na,SO (ac) + H2O(1) d. CHg(
Debora [2.8K]

Answer:

a. S(s) + 3/2 O₂(g) → SO₃(g)

b. Al(s) + 3/2 Cl₂(g) → AICI₃(s)

c. 2 NaOH(s) + H₂SO₄(ac) → Na₂SO₄(ac) + 2 H₂O(l)

d. C₃H₈(g) + 5 O₂(g) → 3 CO₂(g) +  4 H₂O(g)

Explanation:

We will balance the equation using the trial and error method.

a. S(s) + O₂(g) → SO₃(g)

1. We will balance O atoms by multiplying O₂by 3/2.

S(s) + 3/2 O₂(g) → SO₃(g)

b. Al(s) + Cl₂(g) → AICI₃(s)

1. We will balance Cl atoms by multiplying Cl₂ by 3/2.

Al(s) + 3/2 Cl₂(g) → AICI₃(s)

c. NaOH(s) + H₂SO₄(ac) → Na₂SO₄(ac) + H₂O(l)

1. We will balance Na atoms by multiplying NaOH by 2.

2. We will balance H and O atoms by multiplying H₂O by 2.

2 NaOH(s) + H₂SO₄(ac) → Na₂SO₄(ac) + 2 H₂O(l)

d. C₃H₈(g) + O₂(g) → CO₂(g) +  H₂O(g)

1. We will balance C atoms by multiplying CO₂ by 3.

2. We will balance H atoms by multiplying H₂O by 4.

3. We will balance O atoms by multiplying O₂ by 5.

C₃H₈(g) + 5 O₂(g) → 3 CO₂(g) +  4 H₂O(g)

8 0
3 years ago
How do you know the ph level of 10^-8
sergiy2304 [10]

pH=6.98

Explanation:

This is a very interesting question because it tests your understanding of what it means to have a dynamic equilibrium going on in solution.

As you know, pure water undergoes self-ionization to form hydronium ions, H3O+, and hydroxide anions, OH−.

2H2O(l]⇌H3O+(aq]+OH−(aq]→ very important!

At room temperature, the value of water's ionization constant, KW, is equal to 10−14. This means that you have

KW=[H3O+]⋅[OH−]=10−14

Since the concentrations of hydronium and hydroxide ions are equal for pure water, you will have

[H3O+]=√10−14=10−7M

The pH of pure water will thus be

pH=−log([H3O+])

pH=−log(10−7)=7

Now, let's assume that you're working with a 1.0-L solution of pure water and you add some 10

5 0
3 years ago
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