Answer:
The [OH⁻] of a solution that has a pOH of 2.7 will be 2*10⁻³
Explanation:
The pOH (or potential OH) is a measure of the basicity or alkalinity of a solution.
pOH indicates the concentration of hydroxyl ions [OH-] present in a solution. In this way, pOH is defined as the negative logarithm of the activity of hydroxide ions, that is, the concentration of OH- ions:
pOH= -log [OH⁻]
In this case, pOH has a value of 2.7. Replacing:
2.7= -log [OH⁻]
and solving:
[OH⁻]=10⁻² ⁷
you get:
[OH⁻]≅ 2*10⁻³
<u><em>The [OH⁻] of a solution that has a pOH of 2.7 will be 2*10⁻³</em></u>
Answer:
hydrogen gas
Explanation: Magnesium combined with sulfuric acid produces magnesium sulfate and hydrogen gas
Explanation:
Answer:
1.32 mole
Explanation:
The following data were obtained from the question:
Volume of solution = 2.2L
Molarity of solution = 0.60M
Mole of Li3PO4 =..?
Molarity is simply defined as the mole of solute per unit litre of the solution. Mathematically, it is represented as:
Molarity = mole /Volume
With the above formula we can easily calculate the number of mole of Li3PO4 as shown below:
Molarity =mole /Volume
0.6 = mole of Li3PO4 /2.2
Cross multiply
Mole of Li3PO4 = 0.6 x 2.2
Mole of Li3PO4 = 1.32 mole
Therefore, 1.32 mole of Li3PO4 is contained in the solution.
Answer:
174 K
Explanation:
To answer this question we will use the PV=nRT formula, where:
We <u>input the data</u> given by the problem:
- 1.072 atm * 20.0 L = 1.50 mol * 0.082atm·L·mol⁻¹·K⁻¹ * T
And <u>solve for T</u>:
Meaning the correct answer is the fourth option, 174 K.
The answer is D, pH greater than 7. This is because when you make a solution of potassium hydroxide, it leads to an excess of hydroxide ions in the water. Since the concentration of hydroxide ions is greater than that of protons, it causes the water to be basic. The basic range on the pH scale is always greater than 7.
