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3 years ago

A steel calorimeter has a volume of 75.0 mL and is charged with Oxygen gas to a

Chemistry

1 answer:

EastWind [94]3 years ago

7 0

Answer:

7.78×10¯³ mole

Explanation:

From the question given above, the following data were obtained:

Volume (V) = 75 mL

Pressure (P) = 255 kPa

Temperature (T) = 22.5 °C

Number of mole (n) =?

Next, we shall convert 75 mL to L. This can be obtained as follow:

1000 mL = 1 L

Therefore,

75 mL = 75 mL × 1 L / 1000 mL

75 mL = 0.075 L

Next, we shall convert 22.5 °C to Kelvin temperature. This can be obtained as follow:

T(K) = T(°C) + 273

Temperature (T) = 22.5 °C

Temperature (T) = 22.5 °C + 273

Temperature (T) = 295.5 K

Finally, we shall determine the amount of oxygen molecules present in steel calorimeter. This can be obtained as follow:

Volume (V) = 0.075 L

Pressure (P) = 255 kPa

Temperature (T) = 295.5 K

Gas constant (R) = 8.314 KPa.L/Kmol

Number of mole (n) =?

PV = nRT

255 × 0.075 = n × 8.314 × 295.5

19.125 = n × 2456.787

Divide both side by 2456.787

n = 19.125 / 2456.787

n = 7.78×10¯³ mole

Thus, amount of oxygen molecules present in steel calorimeter is 7.78×10¯³ mole

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2 years ago

Sulfonation of benzene has the following mechanism: (1) 2 H2SO4 ⇌ H3O+ + HSO4− + SO3 [fast] (2) SO3 + C6H6 → H(C6H5+)SO3− [slow]

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Question is incomplete, complete question is as follows :

Complete Question : .Sulfonation of benzene has the following mechanism:

(1) 2 H2SO4 ⇌ H3O+ + HSO4− + SO3

[fast]

(2) SO3 + C6H6 → H(C6H5+)SO3−

[slow]

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[fast]

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[fast]

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Rate=k(________/_________)

Answer:

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Explanation :

Frist of all, all the common terms are cancelled out and written the overall reaction.

As we know that the rate depednant step is the slowest step of the reaction, rate law is :

rate = $k_{2} [SO_{3}][C_{6}H_{6}]$

But the problem is that SO3 cannot be written in the overall rate law because it is an intermediate.

Rate law for synthesis of S03 is as follows :

rate = $k_{1}[H_{2}SO_{4}]^{2}$

Hence when we substitute equation 2 in equation one,

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Explanation:

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learn more:

Atomic orbitals brainly.com/question/1832385

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