its electrical energy -------> light and heat
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Answer:
333g/L
Explanation:
The moles of CaCl2 in 6mEq are:
6mEq * (1mmol / 2mEq) = 3mmol CaCl2.
<em>2Eq / mol because the charge of Ca is 2+</em>
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The mass is:
3mmol CaCl2 * (111mg/mmol) = 333mg = 0.333g
<em>Molar mass: 2*35.5g/mol + 40g/mol = 111g/mol = 111mg/mmol</em>
The liters are:
1mL * (1L / 1000mL) = 1x10⁻³L
The concentration in grams per liter is:
0.333g / 1x10⁻³L = 333g/L
Answer:
A. 2.74g is the correct answer
Explanation:
<h3>Greetings!</h3>
where, the sum of abundance always have to be 100%
Thus, 40.0 +60.0= 100.0
Answer:
219.78 mL of the stock solution are needed
Explanation:
First, we take a look at the desired Al2(SO4)3 working solution. We are told that the we need 400 mL of an aqueous aluminum sulfate solution 1.0 M. Let's see how many moles of the compound we have in the desired volume:
1000 mL Al2(SO4)3 solution ----- 1 mole of Al2(SO4)3
400 mL Al2(SO4)3 solution ----- x = 0.4 moles of Al2(SO4)3
To reach the desired concentration in the working solution we need 0.4 moles of Al2(SO4)3 in 400 mL, so we calculate the volume of the stock solution needed to prepare the working solution:
1.82 moles Al2(SO4)3/L = 1.82 M → This is the molar concentration of the stock solution.
1.82 moles of Al2(SO4)3 ----- 1000 mL
0.4 moles of Al2(SO4)3 ----- x = 219.78 mL
So, if we take 219.78 mL of the 1.82 M stock solution, we put it in a graduated cylinder and we dilute it to 400 mL, we would obtain a 1.0 M Al2(SO4)3 solution.
Option 4. ratio of electrons to protons
Isotope that has atomic number of 82 is stable. An element that has an atomic number ∠82 more stable except Tc and Pm. Also there is the concept that isotopes consisting a combination of even-even,even-odd,odd-even, and odd-odd are all stable. Many isotopes with no magic numbers of nucleons are stable
