1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
kramer
3 years ago
9

A projectile is fired at a velocity of 50 m/s straight into the air. What is the velocity of the projectile when the objects dis

placement is 16 meters and headed downward?
Physics
1 answer:
Arisa [49]3 years ago
8 0

Answer:

the final velocity of the object is 53.04 m/s.

Explanation:

Given;

initial velocity of the projectile, u = 50 m/s

displacement of the object, d = 16 m

let the final velocity of the object = v

Apply the following kinematic equation to determine the final velocity of the projectile.

v² = u² + 2gd

v² = 50² + (2 x 9.8 x 16)

v² = 2813.6

v = √2813.6

v = 53.04 m/s

Therefore, the final velocity of the object is 53.04 m/s.

You might be interested in
An Austin volleyball player bumps a 5 kg ball into the air. It reaches a height of 2.8 meters. How fast was the ball going as it
KATRIN_1 [288]

Answer:

v = 7.4 m/s

Explanation:

Given that,

Mass if a volleyball, m = 5 kg

The ball reaches a height of 2.8 m

We need to find how fast the ball is going as it bumped into the air. Ket the velocity is v. Using the conservation of energy to find it as follows :

mgh=\dfrac{1}{2}mv^2\\\\v=\sqrt{2gh} \\\\v=\sqrt{2\times 9.8\times 2.8} \\\\=7.4\ m/s

So, the required speed is 7.4 m/s. Hence, the correct option is (b).

6 0
3 years ago
What is buoyant force on the ball? Question 9 on student exploration: Archimedes Princable
mariarad [96]
Mass of the displaced material. In water it would be the mass of the water that the volume of the ball displaces.
3 0
3 years ago
Which warning sign suggests being bullied?
Vikentia [17]

Answer:

when you tell someone over and over to stop bothering you and they dont so i think you should tell a teacher

Explanation:

6 0
3 years ago
Sort the forces as producing a torque of positive, negative, or zero magnitude about the rotational axis identified in part
Fantom [35]

a) Angular acceleration: 17.0 rad/s^2

b) Weight: conterclockwise torque, reaction force: zero torque

Explanation:

a)

In this problem, you are holding the pencil at its end: this means that the pencil will rotate about this point.

The only force producing a torque on the pencil is the weight of the pencil, of magnitude

W=mg

where m is the mass of the pencil and g the acceleration of gravity.

However, when the pencil is rotating around its end, only the component of the weight tangential to its circular trajectory will cause an angular acceleration. This component of the weight is:

W_p =mg sin \theta

where \theta is the angle of the rod with respect to the vertical.

The weight act at the center of mass of the pencil, which is located at the middle of the pencil. So the torque produced is

\tau = W_p \frac{L}{2}=mg\frac{L}{2} cos \theta

where L is the length of the pencil.

The relationship between torque and angular acceleration \alpha is

\tau = I \alpha (1)

where

I=\frac{1}{3}mL^2

is the moment of inertia of the pencil with respect to its end.

Substituting into (1) and solving for \alpha, we find:

\alpha = \frac{\tau}{I}=\frac{mg\frac{L}{2}sin \theta}{\frac{1}{3}mL^2}=\frac{3 g sin \theta}{2L}

And assuming that the length of the pencil is L = 15 cm = 0.15 m, the angular acceleration when \theta=10^{\circ} is

\alpha = \frac{3(9.8)(sin 10^{\circ})}{2(0.15)}=17.0 rad/s^2

b)

There are only two forces acting on the pencil here:

- The weight of the pencil, of magnitude mg

- The normal reaction of the hand on the pencil, R

The torque exerted by each force is given by

\tau = Fd

where F is the magnitude of the force and d the distance between the force and the pivot point.

For the weight, we saw in part a) that the torque is

\tau =mg\frac{L}{2} cos \theta

For the reaction force, the torque is zero: this is because the reaction force is applied exctly at the pivot point, so d = 0, and therefore the torque is zero.

Therefore:

- Weight: counterclockwise torque (I have assumed that the pencil is held at its right end)

- Reaction force: zero torque

8 0
3 years ago
The Kyoto protocol works by _______.
Lapatulllka [165]
The answer is voluntary involvement! :D Welcome
7 0
3 years ago
Read 2 more answers
Other questions:
  • #2 A car accelerates from rest at 4 m/s^2. What is the velocity of the car after 4 second?
    14·1 answer
  • A circuit element consists of a resistor with value 20Ω and inductor with value 10mH connected in series. A voltage of LaTeX: v(
    8·1 answer
  • Which kinds of objects emit visible light in the electromagnetic spectrum?
    13·1 answer
  • Your town is considering building a hydroelectric power plant. Describe at least two advantages and two disadvantages of this pr
    9·2 answers
  • A car is traveling to the right with a speed of 29m/s ​ when the rider slams on the accelerator to pass another car. The car pas
    11·1 answer
  • Consider a current carrying a wire coming out of your computer screen towards you. Which statement below correctly describes the
    6·1 answer
  • PLEASE HELP ME this is due in 20 mins!!!!!
    9·1 answer
  • Which quantity is represented by the area under a force-time graph?
    9·1 answer
  • A 100kg couch is being pushed with 196N of force. As it slides along the ground it experiences a coefficient of friction of 0.1.
    8·1 answer
  • Physics acceleration
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!