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kramer
3 years ago
9

A projectile is fired at a velocity of 50 m/s straight into the air. What is the velocity of the projectile when the objects dis

placement is 16 meters and headed downward?
Physics
1 answer:
Arisa [49]3 years ago
8 0

Answer:

the final velocity of the object is 53.04 m/s.

Explanation:

Given;

initial velocity of the projectile, u = 50 m/s

displacement of the object, d = 16 m

let the final velocity of the object = v

Apply the following kinematic equation to determine the final velocity of the projectile.

v² = u² + 2gd

v² = 50² + (2 x 9.8 x 16)

v² = 2813.6

v = √2813.6

v = 53.04 m/s

Therefore, the final velocity of the object is 53.04 m/s.

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Bob and John are pulling in different directions. If Bob is pulling to the right with a force of 10N, and John is pulling to the
Murljashka [212]

Answer:

The net force on the box is 2 N to the left.

The box will move to the left.

The acceleration on the box is 0.5 m/s^2 to the left.

Explanation:

Let's say movement to the right is positive and left is negative.

Bob: +10 N

John: -12 N

Add those together and you get a net force of -2 N, and the negative sign means that the box is moving to the left.

For the acceleration:

Fnet = ma

-2 = (4 kg)a

a = -0.5 m/s^2

Again, the negative sign in this answer means the box is being accelerated to the left.

4 0
3 years ago
A box has a mass of 150kg and the surface area of the bottom of the box is :
charle [14.2K]

Answer:

Pressure = 100 Pascals

Explanation:

pressure =  \frac{force}{area}  \\  =  \frac{150 \times 10}{15}  \\  =  \frac{1500}{15}  \\  = 100 pa

3 0
3 years ago
A wheel that is rotating at 33.3 rad/s is given an angular acceleration of 2.15 rad/s 2. Through what angle has the wheel turned
Neporo4naja [7]

Answer:

The angle through which the wheel turned is 947.7 rad.

Explanation:

initial angular velocity, \omega _i = 33.3 rad/s

angular acceleration, α = 2.15 rad/s²

final angular velocity, \omega_f = 72 rad/s

angle the wheel turned, θ = ?

The angle through which the wheel turned can be calculated by applying the following kinematic equation;

\omega_f^2 = \omega_i^2 + 2\alpha \theta\\\\\theta = \frac{\omega_f^2\   -\  \omega_i^2}{2\alpha } \\\\\theta = \frac{(72)^2\   -\  (33.3)^2}{2(2.15)}\\\\\theta = 947.7 \ rad

Therefore, the angle through which the wheel turned is 947.7 rad.

5 0
2 years ago
A car of mass 750 kg accelerates away from traffic lights. At the end of the first 100 m it has reached a speed
malfutka [58]

the work done on the car by the force of its engine is 78,000 J.

" The work done on the car by the force of friction is 24,000 J.

Increasing the car's kinetic energy at the end of the first 100 m is 54,000J

a. Completed work = force x distance. Engine output = 780 N, that is,

780 N x 100 m = 78,000 J.

b. Completed work = force x distance. Friction force = 240 N, that is,

240 N x 100 m = 24,000 J.

c. Kinetic energy = 1 \ 2 x m x v2

= 1 \ 2 x 750 kg x 12 squared = 375 x 144 = 54,000 J.

<h3>How powerful is the engine of a car? </h3>

Mainstream car and truck engines typically produce 100-400 pounds. -Torque feet. This torque is generated by the engine piston as it moves up and down on the engine crankshaft, causing the engine to rotate (or twist) continuously.

Learn more about work done here:  brainly.com/question/25573309

#SPJ10

5 0
2 years ago
PLEASE HELP SOLVE THIS PHOTO BELOW
polet [3.4K]

Answer:

C

Explanation:

The pattern is adding .5 to the cm every .1 in weight you just continue the table

8 0
3 years ago
Read 2 more answers
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