Answer:
Magnification = 1
Explanation:
given data
radius of curvature r = - 0.983 m
image distance u = - 0.155
solution
we get here first focal length that is
Focal length, f = R/2 ...................1
f = -0.4915 m
we use here formula that is
.................2
put here value and we get
<h3>v = 0.155 m </h3>
so
Magnification will be here as
m = ![- \frac{v}{u}](https://tex.z-dn.net/?f=-%20%5Cfrac%7Bv%7D%7Bu%7D)
m =
<h3>m = 1</h3>
Answer:
Final image size is increasing and it is moving away from the focus on the other side
Explanation:
As the object is moving towards the focus of the lens
Then the size of image will start increasing and also the image is formed between focus and double focus point
So we can say that size of image will start increases and the position of image is start moving away from the focus on the other side of the lens
In both the case the image must be Real and diminished and its size is start increasing due to the formula
[tex]M = \frac{d_i}{d_o}[/tex
So here present
Final image size is increasing and it is moving away from the focus on the other side
Answer:
Up first are Mercury and Venus. Neither of them has a moon. Because Mercury is so close to the Sun and its gravity, it wouldn't be able to hold on to its own moon. Any moon would most likely crash into Mercury or maybe go into orbit around the Sun and eventually get pulled into it.