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1 answer:
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Answer:
(d) 0.15 N
Explanation:
mass of the fish, m₁ = 65 g = 0.065 kg
initial velocity of the fish, u₁ = 0
mass of water expelled by the fish, m₂ = 0.30 g = 0.0003 kg
time during which the water was expelled, t = 5.0 ms = 5.0 x 10⁻³ s
velocity of the water, v = 2.5 m/s
The magnitude of force of the exerted water is equal to the magnitude of force the fish exerted on the water.
The magnitude of force of the exerted water is calculated as follows;
The correct option is D.
Therefore, the average force the fish exerts on the drop of water is 0.15 N.
Answer:
The number of liters of ice water is 11 L
Explanation:
Given data:
normal body temperature = 37°C
temperature of the ice water = 0°C
Cwater = specific heat of water = 4186 J/kg °C
Suppose the person drinks 1 L of cold water, then, the mass is 1 kg
The heat is:
The sign (-) indicates the energy lost by the metabolic process. If the Qwalk is 390 kilocalories, then the number of liters of ice water is equal to: