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2 years ago

A person drives a car around a circular road with a constant speed of 20 m/s. The

Physics

2 answers:

soldi70 [24.7K]2 years ago

6 0

16 m/s2 is the answer

ale4655 [162]2 years ago

5 0

Answer:

16 m/s^2

Explanation:

acceleration tangential = (v^2)/r

a=400/25

a=16 m/s^2

Side note: next time, be more specific when asking about acceleration in circular motion. There's more than one type! Example:

angular acceleration=acceleration tangential/r

angular acc.=16/25

angular acc.=0.64 rad/s^2

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2 years ago

g How many diffraction maxima are contained in a region of the Fraunhofer single-slit pattern, subtending an angle of 2.12°, for

lbvjy [14]

Answer:

Explanation:

We know that in the Fraunhofer single-slit pattern,

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Given values

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2 years ago

To test the quality of a tennis ball, you drop it onto the floor from a height of 4.00 m. It rebounds to a height of 2.00 m. If

arlik [135]

Answer:

Part a)

$a = 1260.3 m/s^2$

Part b)

Direction = upwards

Explanation:

When ball is dropped from height h = 4.0 m

then the speed of the ball just before it will strike the ground is given as

$v_f^2 - v_i^2 = 2 a d$

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Now ball will rebound to height h = 2.00 m

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Part a)

Average acceleration is given as

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Part B)

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2 years ago

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Answer:

Explanation:

6000 km

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