Answer:
opposite direction
Explanation:
An electric field is defined as a physical field which surrounds the electrically charged particles that exerts force on the other particles on the field.
Now when an electron or a negatively charged particle enters a uniform electric field, the electric forces acts on the negatively charged particles and it forces the particle to move in the direction which is opposite to the direction of the field. In an uniform electric field, the field lines are parallel.
Answer:
c) nonzero, directed toward the spaceship
Explanation:
As we know that net gravitational force due to spherical shell inside all its points will always be zero
So if planet is a spherical shell then inside the planet net gravitational force is zero on the people living in it
So when massive spaceship land on the surface of planet then the gravitational force of the spaceship is experienced by the people inside the shell
So here the gravitational force on the people is nonzero and it is towards the spaceship which landed on the surface of planet
Answer:
At the midpoint of the line joining the two equal charges
Explanation:
The midpoint of the line joining the two equal charges has equal distance from each charge. Since the charges are at x = a and x = -a, at the midpoint of the line joining the two equal charges, the magnitude of the electric field experienced as a result of each charge is the same. But these two fields are in opposite direction, hence the net resulting electric field would be equal to zero.
Answer:
The potential difference through which an electron accelerates to produce x rays is
.
Explanation:
It is given that,
Wavelength of the x -rays, 
The energy of the x- rays is given by :

The energy of an electron in terms of potential difference is given by :

So,

V is the potential difference
e is the charge on electron


V = 12431.25 volts
or

So, the potential difference through which an electron accelerates to produce x rays is
. hence, this is the required solution.
Tha atmosphere has no effect on gravity.