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3 years ago

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A 1500-W electric heater is plugged into the outlet of a 120-V circuit that has a 20-A circuit breaker. You plug an electric hai

r dryer into the same outlet. The hair dryer has power settings of 600 W, 900 W, 1200 W, and 1500 W. You start with the hair dryer on the 600-W setting and increase the power setting until the circuit breaker trips. What power setting caused the breaker to trip?

1 answer:

tekilochka [14]3 years ago

6 0

Answer:

900 W.

Explanation:

Given that

Electric heater 1500 W

We know that power P given as

P= V I

So the total power of 120 V and 20 A circuit

P = 120 x 20

P= 2400 W

So the power new load P'

P'= Total system power(P)- Electric heater load

P ' = 2400 - 1500

P'= 900 W

So the answer is 900 W.

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$F=\frac{\Delta p}{\Delta t} =\frac{56m_{b}\ m/s}{0.020s} =2800m_{b} \ m/s^{2}$

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Answer:

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Applying conservation of energy again

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