Answer:
13 , 17 and 25 cm.
Step-by-step explanation:
Let the length of the first side be x cm.
Then the second is x+4 and the third is 2x-1 cm long.
As the perimeter = 55 cm we have the equation:
x + x + 4 + 2x - 1 = 55
4x + 3 = 55
4x = 52
x = 13 cm.
Answer:
Step-by-step explanation:
GIVEN: A farmer has of fencing to construct a rectangular pen up against the straight side of a barn, using the barn for one side of the pen. The length of the barn is .
TO FIND: Determine the dimensions of the rectangle of maximum area that can be enclosed under these conditions.
SOLUTION:
Let the length of rectangle be and
perimeter of rectangular pen
area of rectangular pen
putting value of
to maximize
but the dimensions must be lesser or equal to than that of barn.
therefore maximum length rectangular pen
width of rectangular pen
Maximum area of rectangular pen
Hence maximum area of rectangular pen is and dimensions are
2nd answer.
any pts in the shaded region satisfies your simultaneous equation.
Answer:
Step-by-step explanation:
The equation of a line in slope-intercept form is
y = mx + b
We need to find the slope, m, and the y-intercept, b.
The line we need is perpendicular to the line 2x + y = 8.
<em>The slopes of perpendicular lines are negative reciprocals.</em>
We solve the given equation for y to find the slope of the given line.
2x + y = 8
y = -2x + 8
The given line has slope -2.
The negative reciprocal of -2 is 1/2.
Our line has slope, m = 1/2.
Now we have
y = 1/2 x + b
Now we use the given point, (-2, 3), for x and y, using x = -2, and y = 3, and we solve for b.
y = 1/2 x + b
3 = 1/2 * (-2) + b
3 = -1 + b
4 = b
b = 4
Now we have
y = 1/2 x + 4
Answer:
Answer:
F = 3x +(2.7×10^7)/x
Step-by-step explanation:
The formulas for area and perimeter of a rectangle can be used to find the desired function.
<h3>Area</h3>
The area of the rectangle will be the product of its dimensions:
A = LW
Using the given values, we have ...
13.5×10^6 = xy
Solving for y gives ...
y = (13.5×10^6)/x
<h3>Perimeter</h3>
The perimeter of the rectangle is the sum of the side lengths:
P = 2(L+W) = 2(x+y)
<h3>Fence length</h3>
The total amount of fence required is the perimeter plus one more section that is x feet long.
F = 2(x +y) +x = 3x +2y
Substituting for y, we have a function of x:
F = 3x +(2.7×10^7)/x
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<em>Additional comment</em>
The length of fence required is minimized for x=3000. The overall size of that fenced area is x=3000 ft by y=4500 ft. Each half is 3000 ft by 2250 ft. Half of the total 18000 ft of fence is used for each of the perpendicular directions: 3x=2y=9000 ft.