Do you think the reasoning you used to make

malfutka [58]

Radioactive isotope, also called radioisotope, radionuclide, or radioactive nuclide, any of several species of the same chemical element with different masses whose nuclei are unstable and dissipate excess energy by spontaneously emitting radiation in the form of alpha, beta, and gamma rays.

4 0

4 years ago

The gas OF2 can be produced from the electrolysis of an aqueous solution of KF, as shown in the equation below.

Readme [11.4K]

Answer:

A) 6.48 g of OF₂ at the anode.

Explanation:

The gas OF₂ can be obtained through the oxidation of F⁻ (inverse reaction of the reduction presented). The standard potential of the oxidation is the opposite of the standard potential of the reduction.

H₂O(l) + 2 F⁻(aq) → OF₂(g) + 2 H⁺(aq) + 4 e⁻ E° = -2.15 V

Oxidation takes place in the anode.

We can establish the following relations:

1 Faraday is the charge corresponding to 1 mole of e⁻.
1 mole of OF₂ is produced when 4 moles of e⁻ circulate.
The molar mass of OF₂ is 54.0 g/mol.

The mass of OF₂ produced when 0.480 F pass through an aqueous KF solution is:

$0.480F.\frac{1mole^{-} }{1F} .\frac{1molOF_{2}}{4mole^{-} } .\frac{54.0gOF_{2}}{1molOF_{2}} =6.48gOF_{2}$

7 0

3 years ago

What is a relationship where one organism benefits while the other gets nothing

andreev551 [17]

The answer is <span>commensalism</span>

8 0

4 years ago

If I have 4.5 liters of gas at a temperature of 33 0C and a pressure of 6.54 atm, what will be the pressure of the gas if I rais

Nikitich [7]

This is an exercise in the general or combined gas law.

To start solving this exercise, we must obtain the following data:

V₁ = 4.5 l
T₁ = 33 °C + 273 = 306 k
P₁ = 6.54 atm
T₂ = 94 °C + 273 = 367 k
V₂ = 2.3 l
P₂ = ¿?

We use the following formula:

P₁V₁T₂ = P₂V₂T₁ ⇒ General Formula

Where

P₁ = Initial pressure
V₁ = Initial volume
T₂ = Initial temperature
P₂ = Final pressure
V₂ = Final volume
T₁ = Initial temperature

We clear the general formula for the final pressure.

$\large\displaystyle\text{$\begin{gathered}\sf P_{2}=\frac{P_{1}V_{1}T_{2} }{V_{2}T_{1}} \ \to \ Clear \ formula \end{gathered}$}$

We solve by substituting our data in the formula:

$\large\displaystyle\text{$\begin{gathered}\sf P_{2}=\frac{(6.54 \ atm)(4.5 \not{l})(367 \not{K}) }{(2.3 \not{l})(306 \not{k})} \end{gathered}$}$

$\large\displaystyle\text{$\begin{gathered}\sf P_{2}=\frac{10800.81}{ 703.8 } \ atm \end{gathered}$}$

$\boxed{\large\displaystyle\text{$\begin{gathered}\sf P_{2}=15.346 \ atm \end{gathered}$} }$

If I raise the temperature to 94°C and decrease the volume to 2.3 liters, the pressure of the gas will be 15,346 atm.

8 0

2 years ago

Read 2 more answers

After observing (you can repeat the process more than once), write a general statement explaining how reducing the volume change

ad-work [718]

Answer:

The correct answer is that both molecular motion, pressure and temperature increase as volume reduces.

Explanation:

A reduction in volume changes the molecular motion, temperature and pressure of the system. When the volume of the container decreases, this causes the pressure to increase, the temperature to increase and the molecular motion to increase. This is because a liquid and a solid are incompressible, so by reducing the volume of a gas, the molecules increase their movement as the temperature of the system increases, which is due to the increased pressure applied to reduce the volume of the system.

Have a nice day!

4 0

3 years ago