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lubasha [3.4K]
3 years ago
7

Comparing it to how you did back in September; how did you do? (full sentence response) *

Chemistry
2 answers:
In-s [12.5K]3 years ago
8 0
What are we supposed to be answering
GarryVolchara [31]3 years ago
3 0
Comparing what to how I did back in September?
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Help please I’m confused
Debora [2.8K]

Answer:1 answer number 1

Explanation:

5 0
3 years ago
Which is the balanced chemical equation representing the reaction between barium sulfide and platinum fluoride? BaS + PtF2 BaF2
Svetllana [295]

BAS might be an improperly capitalized: BAs, BaS

PTF2 might be an improperly capitalized: PtF2

BAF2 might be an improperly capitalized: BaF2

PTS might be an improperly capitalized: PtS

8 0
3 years ago
Read 2 more answers
Jim can jog 800 m in 16 minutes. How many meters can he jog<br> in a minute?
RSB [31]

Answer: 50 meters

Explanation:

5 0
3 years ago
What is the mass in grams of 3.0x10^23 molecules of carbon dioxide??
Sonja [21]
Moles of CO2 = number of molecules / 6.02x10^23. = 3x10^23/6.02x10^23 = 0.5moles. Therefore, mass of CO2 = moles x molecular mass of CO2= 0.5x44 = 22gm.
4 0
3 years ago
How many moles are in 1.42 x 10^25<br> molecules of NaCl?
Sholpan [36]
<h3>Answer:</h3>

23.6 mol NaCl

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

<u>Stoichiometry</u>

  • Reading a Periodic Table
<h3>Explanation:</h3>

<u>Step 1: Define</u>

1.42 × 10²⁵ molecules NaCl

<u>Step 2: Identify Conversions</u>

Avogadro's Number

<u>Step 3: Convert</u>

  1. Set up:                             \displaystyle 1.42 \cdot 10^{25} \ molecules \ NaCl(\frac{1 \ mol \ NaCl}{6.022 \cdot 10^{23} \ molecules \ NaCl})
  2. Multiply/Divide:                                                                                                   \displaystyle 23.5802 \ mol \ NaCl

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

23.5802 mol NaCl ≈ 23.6 mol NaCl

3 0
2 years ago
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