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Marizza181 [45]
3 years ago
10

A 5.0-kg bag of groceries is tossed onto a table at 2.0 m/s and slides to a stop in 1.6 s .

Physics
1 answer:
son4ous [18]3 years ago
5 0

Answer:

-6.3 N

Explanation:

The equation we need to use is:

F \Delta t = \Delta (mv)

where

F is the force of friction, that slows down the bag

\Delta t is the time of the motion

m is the mass of the bag

v is the speed of the bag

Since the mass of the bag does not change, we can rewrite the equation as

F \Delta t= m \Delta v

where we have:

\Delta t=1.6 s\\m=5.0 kg\\\Delta v=-2.0 m/s

Substituting and re-arranging the equation, we can find the force of friction:

F=\frac{m\Delta v}{\Delta t}=\frac{(5.0 kg)(-2.0 m/s)}{1.6 s}=-6.3 N

where the negative sign means that the force is in the opposite direction to the motion of the bag.

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Given,

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