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Veseljchak [2.6K]
3 years ago
12

Which stimulant drug leads to a brief 15 to 30 minute rush of euphoria and energy followed by a crash and immediate craving for

more?
Physics
1 answer:
solmaris [256]3 years ago
8 0

Answer:

ketamine.

Explanation:

yoda told me.

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A batter hits a baseball with a bat. The bat exerts a force on the ball. Does the ball exert a force on the bat?
Mazyrski [523]
Yes, think about the difference of swinging a bat and not hitting a ball. It's fairly easy right? Now, when you hit a ball with the bat, you will feel the bat sting your hands. That's the force the ball is exerting on the bat!
3 0
3 years ago
Read 2 more answers
Question number 8 <br> Plz help
Dennis_Churaev [7]
To me, that sounds like the "Law of Conservation of Energy".
5 0
3 years ago
Para que el calor sea transmitido por conducción los cuerpos deben tocarse?<br> verdadero o falso
dybincka [34]

Answer:

verdadero

Explanation:

Conducción:Es la más sencilla de entender, consiste en la transferencia de calor entre dos puntos de un cuerpo que se encuentran a diferente temperatura, sin que se produzca transferencia de materia entre ellos.

7 0
3 years ago
Jenny wanted to test whether worms prefer light or darkness best. After
myrzilka [38]

Answer:

True

Explanation:

An independent variable is the variable that is changed or controlled in a scientific experiment to test the effects on the dependent variable. You are changing light or dark

3 0
3 years ago
An object at rest on a flat, horizontal surface explodes into two fragments, one seven times as massive as the other. The heavie
leva [86]

To solve the problem it is necessary to apply conservation of the moment and conservation of energy.

By conservation of the moment we know that

MV=mv

Where

M=Heavier mass

V = Velocity of heavier mass

m = lighter mass

v = velocity of lighter mass

That equation in function of the velocity of heavier mass is

V = \frac{mv}{M}

Also we have that m/M = 1/7 times

On the other hand we have from law of conservation of energy that

W_f = KE

Where,

W_f = Work made by friction

KE = Kinetic Force

Applying this equation in heavier object.

F_f*S = \frac{1}{2}MV^2

\mu M*g*S = \frac{1}{2}MV^2

\mu g*S = \frac{1}{2}( \frac{mv}{M})^2

\mu = \frac{1}{2} (\frac{1}{7}v)^2

\mu = \frac{1}{98}v^2

\mu = \frac{1}{g(98)(5.1)}v^2

Here we can apply the law of conservation of energy for light mass, then

\mu mgs = \frac{1}{2} mv^2

Replacing the value of \mu

\frac{1}{g(98)(5.1)}v^2  mgs = \frac{1}{2}mv^2

Deleting constants,

s= \frac{(98*5.1)}{2}

s = 249.9m

7 0
3 years ago
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