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gregori [183]
3 years ago
8

4. What is the density of water?

Physics
2 answers:
shepuryov [24]3 years ago
8 0

Answer:

the destiny of water is 997 kg/m^3, hope this helps :)

Elodia [21]3 years ago
6 0

Answer:

997 kg/m^3

Explanation:

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Two men decide to use their cars to pull a truck stuck in the mud. They attach ropes and one pulls with a force of 615 N at an a
stiv31 [10]

Answer:

1398.12 N

Explanation:

We define the x-axis in the direction parallel to the movement of the truck  on and the y-axis in the direction perpendicular to it.

x-components  of the ropes forces

T₁x = 615N*cos31°=527.1579 N  :Tension in direction x of the rope of the car 1

T₂x= 961 N*cos25°=870.96 N  :Tension in direction x of the rope of the car 2

Net forward force exerted on the truck in the direction it is headed (Fnx)

Fnx = T₁x  + T₂x

Fnx = 527.1579 N  + 870.96 N

Fnx = 1398.12 N

4 0
4 years ago
Iron filings scattered around a magnet will be most strongly drawn toward the _____.
victus00 [196]
<span>The answer is towards <span>the poles. This is because, at the poles of the magnet, the magnetic field lines get closer together hence indicating that the magnetic force is stronger here. The fields are closest together at the center of the magnet and farthest at the outside side of the magnet. </span></span>




8 0
3 years ago
Read 2 more answers
Identify and define characteristics of both visible and sound waves. These include but are not limited to frequency, pitch, ampl
jeyben [28]
<h3><u>Answer and explanation;</u></h3>
  • <em><u>Sound waves are mechanical waves and are examples of the longitudinal type, a longitudinal wave involves the movement of molecules in the medium parallel to the direction of the wave.</u></em>
  • Sound waves are longitudinal mechanical waves because they move particles parallel to their direction of travel. For example, if a sound wave travels from left to right.
  • <em><u>Pitch is what we perceive as the low or high note quality of a sound. Pitch is determined by the frequency of the sound wave that moved through the air to our eardrums. Frequency is the time taken for a complete oscillation of a wave. </u></em>
  • The more energy or work used to create the vibration, which in turn creates the sound wave, the greater the amplitude of the wave and the louder the sound. Wavelength is the distance between two successive rarefactions or compression in a longitudinal wave.
  • For example, if you were to lightly hit a drum with a drum stick, there would be a softer sound as opposed to the loud boom that would be created if you hit the drum with all of your might
3 0
3 years ago
A ball is projected vertically upward from the surface of the Earth with an initial speed of +49 meters per second. The ball rea
Furkat [3]

Answer:

376.5 m

Explanation:

we know that

s=ut + 1/2 at^2

so here

u=49 m/s

t=5s

and a=g=9.8 m/s^2

so

s= 49×5 +1/2 ×9.8× 5×5

= 254+ 122.5

s= 376.5

7 0
3 years ago
A 280-g mass is mounted on a spring of constant k = 3.3 N/m. The damping constant for this damped system is b = 8.4 x 10^-3 kg/s
yulyashka [42]

Answer:

The number of oscillation is 36.

Explanation:

Given that

Mass = 280 g

Spring constant = 3.3 N/m

Damping constant b=8.4\times10^{-3}\ Kg/s

We need to check the system is under-damped, critical damped and over damped by comparing b with 2m\omega_{0}

2m\omega_{0}=2m\sqrt{\dfrac{k}{m}}

2\sqrt{km}=2\times\sqrt{3.3\times280\times10^{-3}}=1.92kg/s

Here, b<<2m\omega_{0}

So, the motion is under-damped and will oscillate

\omega=\sqrt{\omega_{0}^2-\dfrac{b^2}{4m^2}}

The number of oscillation before the amplitude decays to \dfrac{1}{e} of its original value

A exp(\dfrac{-b}{2m}t)=A exp(-1)

\dfrac{b}{2m}t=1

t = \dfrac{2m}{b}

t=\dfrac{2\times280\times10^{-3}}{8.4\times10^{-3}}

t=66.67\ s

We need to calculate the time period of one oscillation

T=\dfrac{2\pi}{\omega}

T=\dfrac{2\times3.14}{\sqrt{\omega_{0}^2-\dfrac{b^2}{4m^2}}}

T=\dfrac{2\times3.14}{\sqrt{\dfrac{k}{m}-\dfrac{b^2}{4m^2}}}

T=\dfrac{2\times3.14}{\sqrt{\dfrac{3.3}{280\times10^{-3}}-\dfrac{(8.4\times10^{-3})^2}{4\times(280\times10^{-3})^2}}}

T=1.83\ sec

The number of oscillation is

n=\dfrac{t}{T}

n=\dfrac{66.67}{1.83}

n=36

Hence, The number of oscillation is 36.

8 0
3 years ago
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