Answer: The vapor pressure of water at 298 K is 3.565kPa.
Explanation:
The vapor pressure is determined by Clausius Clapeyron equation:
where,
= initial pressure at 298 K = ?
= final pressure at 373 K = 101.3 kPa
= enthalpy of vaporisation = 41.1 kJ/mol = 41100 J/mol
R = gas constant = 8.314 J/mole.K
= initial temperature = 298 K
= final temperature = 373 K
Now put all the given values in this formula, we get
![\log (\frac{101.3}{P_1})=\frac{41100}{2.303\times 8.314J/mole.K}[\frac{1}{298K}-\frac{1}{373K}]](https://tex.z-dn.net/?f=%5Clog%20%28%5Cfrac%7B101.3%7D%7BP_1%7D%29%3D%5Cfrac%7B41100%7D%7B2.303%5Ctimes%208.314J%2Fmole.K%7D%5B%5Cfrac%7B1%7D%7B298K%7D-%5Cfrac%7B1%7D%7B373K%7D%5D)
Therefore, the vapor pressure of water at 298 K is 3.565kPa.
Answer:
dilute solution
A solution containing less solute than the equilibrium amount is called a dilute solution. The solvent has a limited capacity to dissolve a solute.
Explanation:
Answer:
1.26 × 10¹⁵ s⁻¹
Explanation:
Work function is the minimum energy required to remove an electron from the surface of metal
energy of the electron = hf - Φ
Φ = work function = hf₀ where f₀ = threshold frequency
f₀ = Φ / h where h ( Planck constant = 6.626 × 10⁻³⁴ Js)
Φ = 5.22eV = 5.22 × 1 eV where 1 eV = 1.60217662 × 10⁻¹⁹ J
Φ = 5.22 × 1.60217662 × 10⁻19 J = 8.363362 × 10⁻¹⁹ J
f₀ = (8.363362 ×10⁻¹⁹ J) / (6.626× 10⁻³⁴ Js) = 1.26 × 10¹⁵ s⁻¹
The frequency must be greater than the 1.26 × 10¹⁵ s⁻¹ to observe the emission
B.
Dendrites are parts the neuron that receive stimulation in order for the cell to become active.
