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vodka [1.7K]
3 years ago
12

If a sample of gas of valume 605 mL and temperature of 39 OC, has 0,00803 moles. What is it’s pressure?

Chemistry
1 answer:
andrew-mc [135]3 years ago
6 0

Answer: The pressure of the gas is 0.34 atm

Explanation:

According to ideal gas equation:

PV=nRT

P = pressure of gas = ?

V = Volume of gas = 605 ml = 0.605 L      (1L=1000ml)

n = number of moles  = 0.00803

R = gas constant =0.0821Latm/Kmol

T =temperature =39^0C=(39+273)K=312K

P=\frac{nRT}{V}

P=\frac{0.00803\times 0.0821 L atm/K mol\times 312K}{0.605L}=0.34atm

The pressure of the gas is 0.34 atm

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