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Svetllana [295]
2 years ago
10

An ant clings to the outside edge of the tire of an exercise bicycle. When you start pedaling, the ant's speed increases from ze

ro to 12 m/s in3.3 s . The wheel's rotational acceleration is11 rad/s2 .
1: Determine the average tangential acceleration of the tire.
2: Determine the radius of the tire.
3: Determine the angle the ant has turned during this time interval.
4: Determine the distance the ant has traveled along the arc during this time interval.

Physics
1 answer:
konstantin123 [22]2 years ago
3 0

Answer:

1- 3.64 m/s

2- 0.28 m

3- 70.8 rad

4- 19.8 m

Explanation:

see attachment

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The composition of the protoplanetary disk varies with distance from the protostar due to temperature.
lesantik [10]

Answer:

b) 1. Iron, silicates, carbon

   2. Water

   3. Methane, Ammonia, Carbon Dioxide.

Explanation:

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7 0
3 years ago
A firecracker in a coconut blows the coconut into three pieces. Twopieces of equal mass fly off south and west, perpendicular to
loris [4]

Answer:

V = 13m/s

North-East (i.e. 45 degree from North)

Explanation:

This question deals with the idea of momentum.

Since the directions of a compass are fixed, we can take south as horizontal and west as vertical. Since both pieces of coconut are of equal mass, then the resultant of the two pieces would be in between South and West and the third piece would be opposite this direction and be in the North-East (i.e. 45 degree from North) direction

To find the speed of the third piece, we first find the speed on the two pieces of the coconut in terms of V_{x} (horizontal component of velocity) and V_{y} (vertical component of velocity)

We have

V_{y} = Velocity in South direction = 18m/s

m_{y} = Mass of piece in South direction = m

V_{x} = Velocity in West direction = 18m/s

m_{x} = Mass of piece in West direction = m

V_{ry} = Velocity of Third Piece in North direction = unknown

V_{rx} = Velocity of Third Piece in East direction = unknown

m = Mass of third piece = 2m

mV_{ry}  = m_{y} V_{y} \\ 2mV_{ry}  = m18\\ V_{ry} = 9

mV_{rx}  = m_{x} V_{x} \\ 2mV_{rx}  = m18\\ V_{rx} = 9

Since we now know the horizontal and vertical component of the velocity of the third piece of coconut we find the resultant velocity. Since we know the direction is North-East, we can imagine a right angled triangle with base of 9 and height 9 and the hypotenuse equal to the resultant velocity .

We can simply apply the Pythagoras theorem and find the hypotenuse

Hypotenuse^{2}  = Height^{2}  + Base^{2} \\ V_{3}^2  = 9^{2} + 9^{2} \\ V = 12.728 m/s

V = 13m/s

6 0
3 years ago
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