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Ganezh [65]
3 years ago
12

Part 1 of 2

Physics
1 answer:
Readme [11.4K]3 years ago
3 0

Answer:

I got you.. i'm in middle school and had that same question.

Explanation:

Refer to the diagram shown below.

The vertical distance traveled is

s = 25 m

The initial vertical launch velocity is zero.

Therefore

s = (1/2)*g*t²

where g = 9.8 m/s²

t = the time of flight, s

That is,

0.5*9.8*t² = 25

t² = 25/4.9 = 5.102

t = 2.26 s

Answer: 2.26 s

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zavuch27 [327]
Yes I pretty sure it's c
6 0
3 years ago
A 50-cm3 block of wood is floating on water, and a 50-cm3 chunk of iron is totally submerged in the water. Which one has the gre
ludmilkaskok [199]

Answer:

Iron

Explanation:

The buoyant force equals to the weight of water being displaced by the object.

Since, the volume of both iron and wood is equal and the wood is not completely submerged, but the iron block is completely submerged i.e more volume of the water is being displaced by the iron block.

Hence, the buoyant force is more on the iron.

4 0
3 years ago
Fill in the physical properties of oxygen cited in the text: color: solubility in water: freezing point: ?c boiling point: ?c
dexar [7]

Colour: Colourless

Solubility in water: Slight

Freezing point: -218

I didn't get the boiling point

8 0
3 years ago
Read 2 more answers
Two students hear the same sound and their eardrums receive the same power from the sound wave. The sound intensity at the eardr
Margaret [11]

Answer:

a. d₁/d₂ = 1.09 b. 0.054 mW

Explanation:

a. What is the ratio of the diameter of the first student's eardrum to that of the second student?

We know since the power is the same for both students, intensity I ∝ I/A where A = surface area of ear drum. If we assume it to be circular, A = πd²/4 where r = radius. So, A ∝ d²

So, I ∝ I/d²

I₁/I₂ = d₂²/d₁² where I₁ = intensity at eardrum of first student, d₁ = diameter of first student's eardrum, I₂ = intensity at eardrum of second student, d₂ = diameter of second student's eardrum.

Given that I₂ = 1.18I₁

I₂/I₁ = 1.18

Since I₁/I₂ = d₂²/d₁²

√(I₁/I₂) = d₂/d₁

d₁/d₂ = √(I₂/I₁)

d₁/d₂ = √1.18

d₁/d₂ = 1.09

So, the ratio of the diameter of the first student's eardrum to that of the second student is 1.09

b. If the diameter of the second student's eardrum is 1.01 cm. how much acoustic power, in microwatts, is striking each of his (and the other student's) eardrums?

We know intensity, I = P/A where P = acoustic power and A = area = πd²/4

Now, P = IA

= I₂A₂

= I₂πd₂²/4

= 1.18I₁πd₂²/4

Given that I₁ = 0.58 W/m² and d₂ = 1.01 cm = 1.01 × 10⁻² m

So, P = 1.18I₁πd₂²/4

= 1.18 × 0.58 W/m² × π × (1.01 × 10⁻² m)²/4

= 0.691244π × 10⁻⁴ W/4 =

2.172 × 10⁻⁴ W/4

= 0.543 × 10⁻⁴ W

= 0.0543 × 10⁻³ W

= 0.0543 mW

≅ 0.054 mW

3 0
3 years ago
What is the direction of the net force when one force is pulling down and one force is pushing to the right?
motikmotik

Answer:  If the net force on an object is zero, its acceleration will be zero. For example in free fall, the net force on an object equals its weight - the one force pulling on it. If 2 forces push or pull on an object in opposite directions, and the two forces cancel .

Explanation: PLEASE MARK ME AS BRAINLIEST!

7 0
3 years ago
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