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Ganezh [65]
3 years ago
12

Part 1 of 2

Physics
1 answer:
Readme [11.4K]3 years ago
3 0

Answer:

I got you.. i'm in middle school and had that same question.

Explanation:

Refer to the diagram shown below.

The vertical distance traveled is

s = 25 m

The initial vertical launch velocity is zero.

Therefore

s = (1/2)*g*t²

where g = 9.8 m/s²

t = the time of flight, s

That is,

0.5*9.8*t² = 25

t² = 25/4.9 = 5.102

t = 2.26 s

Answer: 2.26 s

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Determine how many times per second it would move back and forth across a 6.0-m-long room on the average, assuming it made very
timofeeve [1]

Answer:

The right solution is "24.39 per sec".

Explanation:

According to the question,

⇒ v=\frac{502.1}{\sqrt{3} }

      =289.9 \ m/s

The time will be:

⇒ t=\frac{d}{v}

      =\frac{2\times 6}{289.9}

      =\frac{12}{289.9}

      =0.041 \ sec

hence,

⇒ N=\frac{1}{t}

        =\frac{1}{0.041}

        =24.39 \ per \ sec

4 0
3 years ago
When you lift a box, what is the effort force?
aleksandrvk [35]

Answer:

effort force: The force used to move an object over a distance. resistance force: The force which an effort force must overcome in order to do work on an object via a simple machine. ideal mechanical advantage: The factor by which a mechanism multiplies the force put into it.

Explanation:

5 0
3 years ago
The focal length of david's lens is 60 cm. if rebecca stands in front of david at a distance of do and david perceives the posit
Makovka662 [10]

if rebecca stands in front of david at a distance of do and david perceives the position of rebecca at di, di will be +84 cm

<h3>What is focal length ?</h3>

How strongly light converges or diverges depends on an optical system's focal length, which is the inverse of optical power. A system with a positive focus length is said to converge light, whereas one with a negative focal length is said to diverge light.

focal length = +60 cm

magnification m = -0.40

focal length being positive an magnification negative.

given lens is a convex lens.

for a lens

m = di/do and 1/f = (1/di) - (1/do)di

= -0.4do1/f = (1/-0.4do) - 1/do do

= -210 cmdi = -0.4 * -210

di = +84 cm

To learn more about focal length go to - brainly.com/question/25779311

#SPJ4

5 0
2 years ago
PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!
Sonbull [250]

Question 1  

In order to do work, the force vector must be

in the same direction as the displacement vector and the motion.

Question 2  

In which of the following cases is work being done on an object?

Pulling a trailer up a hill

Question 3  

Which situation is an example of NOT doing work?

carrying a box

Question 4  

Work is measured in

Joules

Question 5  

To find the work done, the force exerted and distance moved are multiplied. A couch is moved twice before you are happy with its placement. The same force was used to move the couch both times. If more work is done the first time it is moved, what do you know about the distance it was moved?

When more work was done, the couch was moved further.

Question 6  

A weight lifter raises a 1600 N barbell to a height of 2.0 meters. How much work was done? W = Fd

3200 Joules

Question 7  

You and a friend (Alex) are at a a tree-top adventure park .. . . part of the course requires you to climb up a rope. You both climb the same rope in the same amount of time. However, the tension in the rope is greater

when Alex climbs. Who did the most work?

Alex did - more tension means more force - more force means more work was done  

Question 8  

Doing work at a faster rate creates power.

more

Question 9  

In one challenge on the Titan Games, competitors have to lift 200 pounds up a long ramp. Angel is able to move the weight in 42 seconds. Anthony gets it done in only 38 seconds. Which statement is true?

Anthony has more power than Angel.  

Question 10  

A mountain climber exerts 41,000 J of work to climb a cliff. How much power does the climber need if she wants to finish in only 500 seconds? Power = Work / time

82 Watts

Question 11  

Your family is moving to a new apartment. While lifting a box 83 Joules of work is done to put the box on a truck, you exert an upward force of 75 N for 3 s. How much power is required to do this? (Hint: You only need two of the 3 numbers given!) Power = Work / time

27.7 Watts

<em>*100% CORRECT ANSWERS</em>

4 0
3 years ago
3
Elanso [62]

Answer:

ive got no idea just ask your teacher

7 0
3 years ago
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