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natima [27]
3 years ago
14

Experiment with the battery voltage set to 15 volts, measure the current in a parallel circuit with 1,2,3, and 4 light bulbs. (I

n
each case, place the ammeter next to the battery). Use Ohm's Law to calculate the total resistance of the circuit. That is,
measure the current and use R=V/ to calculate the total apparent resistance of the circuit.

Physics
1 answer:
koban [17]3 years ago
3 0

Answer:

1) current = I

2) Resistance = V/I

3) current = 2I

4) resistance = V/2I

5) current = 3I

6) Resistance = V/3I

7) Current = 4I

8) Resistance = V/4I

Explanation:

When one bulb is connected across the battery then let say the current is given as I

Then resistance is given as

R = \frac{V}{I}

When two bulbs are in parallel with the battery then

total current becomes twice of initial current

so we have

current = 2I

Resistance of the circuit is now

R = \frac{V}{2I}

When three bulbs are in parallel with the battery then

total current becomes three times of initial current

so we have

current = 3I

Resistance of the circuit is now

R = \frac{V}{3I}

When four bulbs are in parallel with the battery then

total current becomes four times of initial current

so we have

current = 4I

Resistance of the circuit is now

R = \frac{V}{4I}

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3 years ago
A proton with a velocity in the positive x-direction enters a region where there is a uniform magnetic field B in the positive y
blsea [12.9K]

Answer:

Negative z-direction

Explanation:

First of all, we need to understand the direction of the magnetic force on the proton. This can be determined by using the right hand rule. So we have:

- index finger: direction of the proton, positive x-direction

- middle finger: direction of magnetic field, positive y-direction

- thumb: direction of the force, positive z-direction

In order to balance this magnetic force, the electric force must act in the opposite direction (negative z direction). Since for a proton (positive charge) the force and the electric field have same direction, it means that the electric field must also be in the negative z direction.

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3 years ago
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IgorLugansk [536]
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3 years ago
A 95 kg clock initially at rest on a horizontal floor requires a 650 n horizontal force to set it in motion. after the clock is
Tamiku [17]
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3 years ago
Read 2 more answers
6. A 0.09 kg arrow hits a target at 22 m/s and penetrates 4 cm before stopping.
tatyana61 [14]
A ) v = v o - a t
0 = 22 - a · t
a · t = 22
d = v o · t - a t²/2
0.04 = 22 t - 22 t / 2
0.04 = 11 t
t = 0.04 : 11 = 0.003636 s
a = 22 / t
a = 6050 m/s²
F = m · a = 0.09 kg · 6050 m/s²
F ( target→arrow) = - 544.5 N
b ) F ( arrow→target ) = 544.5 N
c )  If the speed was doubled:  v = 44 m/s;
F = a m
a = 6050 m/s²
a · t = 44
t = 6050 : 0.04
t = 0.007272 s
d = 44 t - 44 t/2 = 22 t
d = 22 · 0.007272
d = 0.16 m = 16 cm
8 0
3 years ago
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