Experiment with the battery voltage set to 15 volts, measure the current in a parallel circuit with 1,2,3, and 4 light bulbs. (I
n
each case, place the ammeter next to the battery). Use Ohm's Law to calculate the total resistance of the circuit. That is,
measure the current and use R=V/ to calculate the total apparent resistance of the circuit.
each case, place the ammeter next to the battery). Use Ohm's Law to calculate the total resistance of the circuit. That is,
measure the current and use R=V/ to calculate the total apparent resistance of the circuit.
1 answer:
Answer:
1) current = I
2) Resistance = V/I
3) current = 2I
4) resistance = V/2I
5) current = 3I
6) Resistance = V/3I
7) Current = 4I
8) Resistance = V/4I
Explanation:
When one bulb is connected across the battery then let say the current is given as I
Then resistance is given as
When two bulbs are in parallel with the battery then
total current becomes twice of initial current
so we have
current = 2I
Resistance of the circuit is now
When three bulbs are in parallel with the battery then
total current becomes three times of initial current
so we have
current = 3I
Resistance of the circuit is now
When four bulbs are in parallel with the battery then
total current becomes four times of initial current
so we have
current = 4I
Resistance of the circuit is now
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The solution(s) are in order with respect to the attachments
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Explanation:
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q = 1.3 kg 2.01
10⁵ J / kg =
=
=
=
Joules =
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The electric field is zero at x = -16.45cm
Data;
- q1 = 3.4 μC
- q2 = -2.0 μC
- distance = 5cm
As the 3μC is larger than -2.0μC and the charges are opposite sign. The electric field will be zero at the negative axis.
Let the point be at x.
For an electric field to be equal to zero;
Let's solve for x using mathematical methods.
Solving the above quadratic equation;
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